<h3>They are 268 miles far apart after 4 hours</h3>
<h3>Further explanation</h3>
Acceleration is rate of change of velocity.


<em>a = acceleration ( m/s² )</em>
<em>v = final velocity ( m/s )</em>
<em>u = initial velocity ( m/s )</em>
<em>t = time taken ( s )</em>
<em>d = distance ( m )</em>
Let us now tackle the problem !
<u>Given :</u>
v₁ = 30 mph due east
v₂ = 60 mph due south
t = 4 hours
<u>Unknown :</u>
displacement = d = ?
<u>Solution :</u>












<h2>Conclusion :</h2><h3>They are 268 miles far apart after 4 hours</h3>
<h3>Learn more</h3>
<h3>Answer details</h3>
Grade: High School
Subject: Physics
Chapter: Kinematics
Keywords: Velocity , Driver , Car , Deceleration , Acceleration , Obstacle , Speed , Time , Rate
What the question?
Or picture
Answer:
(50+40x) dollars
Step-by-step explanation:
THe fixed cost is $50 (this includes everything and 6GB of data).
Now, for every GB <em>OVER</em> 6 GB he uses, company charges $40 extra.
So, if he used "x" GB EXTRA, his EXTRA cost will be 40 * x = 40x
Thus, his total cost in the month would be fixed cost PLUS the extra, which would be
50 + 40x dollars
Answer:
C. 5
Step-by-step explanation:
3x – 7 > – 1
Add 7 to each side
3x – 7+7 > – 1+7
3x> 6
Divide each side by 3
3x/3 >6/3
x >2
X must be greater than 2
Answer:
a) Only the first one is an identity.
Step-by-step explanation:
1). 8 cos O tan O csc O = 8 simplifies to:
cos O tan O csc O = 1
cos O * (sin O / cos O) * (1 /sin O)
= cos O sin O / cos O sin O
= 1
So it is identity.
2) 13 sec^2 O/ cos^2 O - tan^2 O / cos^2O
= 13 sec^2 O - tan^2 O / cos^2 O
Now sec^2 O = 1 + tan^2 O, so we have:
(13( 1 + tan^2 O) - tan^2 O) / cos^2 O
= (12 tan^2 O + 13) / cos^2 O
This is not always = 2 so its not an identity.