Question

A drop of oil is floating between two parallel plates with a separation of 8.3 mm. If the mass of the oil drop is 2.7 x 10-15 kg, and its charge is -9.612 x 10-19 C, determine the voltage across the charged plates and determine which plate is positive.

Answer 1

The voltage across the charged plates is  228.5 V.

Voltage across the plates

V = Fd/q

V = (mgd)/q

where;

• m is mass of the oil
• g is acceleration due to gravity
• d is the distance of separation
• q is charge

V = (2.7 x 10⁻¹⁵ x 9.8 x 8.3 x 10⁻³) / (9.612 x 10⁻¹⁹)

V = 228.5 V

Thus, the voltage across the charged plates is  228.5 V.

Learn more about voltage here: brainly.com/question/14883923

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