Answer:
The net force on the block F(net) = mgsinθ).
Fw =mg(cosθ)(sinθ)
Explanation:
(a)
Here, m is the mass of the block, n is the normal force, \thetaθ is the wedge angle, and Fw is the force exerted by the wall on the wedge.
Since the block sliding down, the net force on the block is along the plane of the wedge that is equal to horizontal component of weight of the block.
F(net) = mgsinθ
The net force on the block F(net) = mgsinθ).
The direction of motion of the block is along the direction of net force acting on the block. Since there is no frictional force between the wedge and block, the only force acting on the block along the direction of motion is mgsinθ.
(b)
From the free body diagram, the normal force n is equal to mgcosθ .
n=mgcosθ
The horizontal component of normal force on the block is equal to force
Fw=n*sin(θ) that exerted by the wall on the wedge.
Substitute mgcosθ for n in the above equation;
Fw =mg(cosθ)(sinθ)
Since, there is no friction between the wedge and the wall, there is component force acting on the wall to restrict the motion of the wedge on the surface and that force is arises from the horizontal component for normal force on the block.
