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Nataly [62]
3 years ago
6

A rock is shot from a catapult at the top of a mountain a height h above a level plain below. The rock is fired at an angle θ ab

ove the horizontal and with an initial vi.(a)Find a symbolic expression in terms of the variables vi, g, and θ for the time at which the rock reaches its maximum height.
Physics
1 answer:
Anika [276]3 years ago
6 0

Answer:

t=\frac{v_{i}Sin\theta }{g}

Explanation:

Let the time taken by the shot to reach to maximum height is t.

initial velocity, vi

angle of projection, θ

Acceleration, g

At maximum height, the vertical component of velocity is zero.

use first equation of motion in vertical motion

v=u+at

0=v_{i}Sin\theta -gt

t=\frac{v_{i}Sin\theta }{g}

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What is the upper block's acceleration if the coefficient of kinetic friction between the block and the table is 0.13?
IgorLugansk [536]

Let us assume that pulley is mass less.

Let the tension produced at both ends of the pulley is T.

We are asked to calculate the acceleration of the block.

Let the masses of two bodies are denoted as m_{1} \ and\ m_{2}\ respectively

Let\ m_{1} =1 kg\ and\ m_{2} =2 kg

As per this diagram, the body having mass 1 kg is moving downward and the body having mass 2 kg is moving on the surface of the table.

Let the acceleration of each block is a .

For body having mass 1 kg:

The net force acting on 1 kg body will be-

                             m_{1} g-T=m_{1} a        [1]

Here tension in the rope will be vertically upward and weight of the body will be in vertical downward direction.

For body having mass 2 kg:

The coefficient of kinetic friction [\mu]=0.13

Hence\ the\ frictional\ force\ F=\mu N

                                                     F=\mu m_{2} g

Hence the net force acting on the body having mass 2 kg-

                                  T-\mu m_{2} g=m_{2} a  [2]

Here the tension of the rope is towards right i.e along the direction of motion of the 2 kg block and frictional force is towards left.

Combining 1 and 2 we get-

                           m_{1} g-T=m_{1}a             [1]

                           T-\mu m_{2}g= m_{2} a   [2]

                           ---------------------------------------------------

                           [m_{1} -\mu m_{2} ]g=[m_{1} +m_{2} ]a

                           a=\frac{m_{1}-\mu m_{2}} {m_{1}+ m_{2}}*g

                           a=\frac{1-[2*0.13]}{1+2} *9.8\ m/s^2

                           a=\frac{0.74}{3} *9.8\ m/s^2

                           a=2.417 m/s         [ans]

6 0
3 years ago
Read 2 more answers
Hitting a home run in baseball is difficult, because it requires a lot of force. Most home runs are hit off of fastballs. Which
OLga [1]

The impact force makes sense because the impulse experienced by the body cause a great change in momentum of the body.

<h3 /><h3>What is impulse?</h3>

This is the force that acts on a body over a given period of time. The impulse experienced by a body is determined as the product of force and time of action.

J = Ft

The change in momentum of a body is equal to the impulse experienced by the body.

ΔP = Ft

Thus, the impact force makes sense because the impulse experienced by the body cause a great change in momentum of the body.

Learn more about impulse here: brainly.com/question/25700778

7 0
2 years ago
Consider hitting a baseball with a bat. If we call the force on the bat against the ball the action force, identify the reaction
Nadya [2.5K]

Answer:

Explanation:

Action and reaction force are an integral part of third law of Newton . They are equal and opposite force - couple which act on two opposite objects. That is why they can not make a body in equilibrium.

In the given case, a bat is hit by a ball , at the point of contact , two equal and opposite forces emerge simultaneously , one acting on the ball and the other acting on the bat. As per the problem , force on the bat is called action . So the other force , that is force acting on the ball is called reaction force.

3 0
3 years ago
What causes friction between two solid forces? After the roughness of the surfaces, what most affects the frictional force exper
Sveta_85 [38]
Friction is caused by two solids rubbing together quickly.

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What is the change in internal energy (in J) of a system that releases 954 J of thermal energy to its surroundings and has 166 c
Harman [31]

Answer:

259.456 J

Explanation:

Given that,

Work done on the system = 166 cal

The systam releases 954 J of thermal energy to its surroundings

We need to find the change in internal energy. It can be given by using the first law of thermodynamics as follows :

\Delta U=Q-W

W = 166 cal = 694.544 (1cal = 4.184 J)

\Delta U=954-694.544\\\\=259.456\ J

So, the change in internal energy of the system is 259.456 J.

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3 years ago
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