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Solnce55 [7]
2 years ago
15

Explain how you can find the constant of proportionality from a graph representing a proportional relationship when it shows a p

oint with an x-value of 1 and if it doesn’t show an x-value of 1.
Mathematics
1 answer:
Korvikt [17]2 years ago
3 0

For a proportional relationship, the constant is found dividing all values of y by each respective value of x.

<h3>What is a proportional relationship?</h3>

A proportional relationship is a function in which the output variable is given by the input variable multiplied by a constant of proportionality, that is:

y = kx

In which k is the constant of proportionality.

The constant can be represented as follows:

k = \frac{y}{x}

Hence the constant is found dividing all values of y by each respective value of x.

More can be learned about proportional relationships at brainly.com/question/10424180

#SPJ1

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claudia is making a gelatin desseert for a party.She plans on making 12 servings for every 5 people.If each pan claudia uses to
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2 years ago
Find f'(x) and state the domain of f':<br> f(x) = In (2x^2+1)
-Dominant- [34]

Answer:

f'(x) = \frac{4x}{2x^2+1}

Domain: All Real Numbers

General Formulas and Concepts:

<u>Algebra I</u>

  • Domain is the set of x-values that can be inputted into function f(x)

<u>Calculus</u>

The derivative of a constant is equal to 0

Basic Power Rule:

  • f(x) = cxⁿ
  • f’(x) = c·nxⁿ⁻¹

Chain Rule: \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)

Derivative: \frac{d}{dx} [ln(u)] = \frac{u'}{u}

Step-by-step explanation:

<u>Step 1: Define</u>

f(x) = ln(2x² + 1)

<u>Step 2: Differentiate</u>

  1. Derivative ln(u) [Chain Rule/Basic Power]:                          f'(x) = \frac{1}{2x^2+1} \cdot 2 \cdot 2x^{2-1}
  2. Simplify:                                                                                       f'(x) = \frac{1}{2x^2+1} \cdot 4x
  3. Multiply:                                                                                                     f'(x) = \frac{4x}{2x^2+1}

<u>Step 3: Domain</u>

We know that we would have issues in the denominator when we have a rational expression. However, we can see that the denominator would never equal 0.

Therefore, our domain would be all real numbers.

We can also graph the differential function to analyze the domain.

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