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3 years ago

6

PLEASE HELP ASAP. Which graph represents this system of inequalities? y < or equal to -3x -2 y > or equal to 2x + 1

1 answer:

igor_vitrenko [27]3 years ago

8 0

<span>To solve the problem shown above, you must apply the following proccedure:

1. You have the following system of inequalities given in the problem above:
</span>
y≤-3x -2
y≥<span>2x + 1

2. When you graph the equations of the line: </span>y =-3x-2 y ; y =2x + 1, and then you evaluate the inequalities, you can obtain the region formed in the first graph.
<span>
Therefore, the answer is: The graph that represents the system of inequalities is the Graph Number 1.</span>

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3 years ago

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3 years ago

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This week, 967 people went to the beach. Last week, 1,189 people went to the beach. The number of people who went to the beach f

zhenek [66]

Answer:

Less than 25%

Step-by-step explanation:

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1.229576008... multiplied by 967 is 1189

This number, 1.229576008..., is a multiplier

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2 years ago

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3 years ago

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Ilia_Sergeevich [38]

Answer:

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Step-by-step explanation:

Given

$\sqrt{8x^7y^8$

Required

Evaluate

$\sqrt{8x^7y^8$

Separate each factor with multiplication sign

$\sqrt{8*x^7*y^8$

Express 8 as 4 * 2 and $x^7$ as $x^6 * x$

$\sqrt{4 * 2 *x^6 * x*y^8$

Split each factor

$\sqrt{4} * \sqrt{2} *\sqrt{x^6} * \sqrt{x}*\sqrt{y^8}$

Evaluate $\sqrt4$

$2 * \sqrt{2} *\sqrt{x^6} * \sqrt{x}*\sqrt{y^8}$

Apply law of indices:

$2 * \sqrt{2} * x^{6*\frac{1}{2}} * \sqrt{x} * y^{8*\frac{1}{2}}$

$2 * \sqrt{2} * x^3 * \sqrt{x} * y^4$

Reorder

$2* x^3 * y^4 * \sqrt{2} * \sqrt{x}$

$2x^3y^4 * \sqrt{2} * \sqrt{x}$

$2x^3y^4 * \sqrt{2*x}$

$2x^3y^4 * \sqrt{2x}$

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Hence:

$\sqrt{8x^7y^8$ $= 2x^3y^4 * \sqrt{2x}$

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3 years ago

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