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3 years ago

8

2. During a 5-day training at your department, the number of visitors tripled each day. If the training started on a Monday with

345 attendees, what was the attendance on Thursday?

1 answer:

bixtya [17]3 years ago

6 0

Monday/345
345×3=
Tuesday/1,035
1,035×3=
Wendsday/3,105
3,105×3
Thursday=9,315

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Suppose approximately 75% of all marketing personnel are extroverts, whereas about 70% of all computer programmers are introvert

Setler [38]

Answer:

$P(x \ge 5) = 1.000$ ---- At least 5 from marketing departments are extroverts

$P(x=15) = 0.013$ ---- All from marketing departments are extroverts

$P(x = 0) = 0.002$ ---------- None from computer programmers are introverts

Step-by-step explanation:

See comment for complete question

The question is an illustration of binomial probability where

$P(x) = ^nC_x * p^x * (1 - p)^{n-x}$

$(a):\ P(x \ge 5)$

$n = 15$ --- marketing personnel

$p = 75\%$ --- proportion that are extroverts

Using the complement rule, we have:

$P(x \ge 5) = 1 - P(x < 5)$

So, we have:

$P(x < 5) =P(x = 0) + P(x = 1) + P(x = 2) + P(x = 3) + P(x = 4)$

$P(x = 0) = ^{15}C_{0} * (75\%)^0 * (1 - 75\%)^{15 - 0} = 1 * 1 * (0.25)^{15} = 9.31 * 10^{-10}$

$P(x = 1) = ^{15}C_{1} * (75\%)^1 * (1 - 75\%)^{15 - 1} = 15* (0.75)^1 * (0.25)^{14} = 4.19 * 10^{-8}$

$P(x = 2) = ^{15}C_{2} * (75\%)^2 * (1 - 75\%)^{15 - 2} = 105* (0.75)^2 * (0.25)^{13} = 8.80 * 10^{-7}$

$P(x = 3) = ^{15}C_{3} * (75\%)^3 * (1 - 75\%)^{15 - 3} = 455* (0.75)^2 * (0.25)^{12} = 0.0000153$

$P(x = 4) = ^{15}C_{4} * (75\%)^4 * (1 - 75\%)^{15 - 4} = 1365 * (0.75)^4 * (0.25)^{11} = 0.000103$

So, we have:

$P(x < 5) = (9.31 * 10^{-10}) + (4.19 * 10^{-8}) + (8.80 * 10^{-7}) + 0.0000153 + 0.000103$

$P(x < 5) = 0.00011922283$

Recall that:

$P(x \ge 5) = 1 - P(x < 5)$

$P(x \ge 5) = 1 - 0.00011922283$

$P(x \ge 5) = 0.9998$

$P(x \ge 5) = 1.000$ --- approximated

$(b)\ P(x = 15)$

$n = 15$ --- marketing personnel

$p = 75\%$ --- proportion that are extroverts

So, we have:

$P(x) = ^nC_x * p^x * (1 - p)^{n-x}$

$P(x=15) = ^{15}C_{15} * 0.75^{15} * (1 - 0.75)^{15-15}$

$P(x=15) = 1 * 0.75^{15} * (0.25)^{0$

$P(x=15) = 0.013$

$(c)\ P(x = 0)$

$n=5$ ---------- computer programmers

$p = 70\%$ --- proportion that are introverts

So, we have:

$P(x) = ^nC_x * p^x * (1 - p)^{n-x}$

$P(x = 0) = ^{5}C_0 * (70\%)^0 * (1 - 70\%)^{5-0}$

$P(x = 0) = 1 * 1 * (0.30)^5$

$P(x = 0) = 0.002$

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2 years ago

Can any one answer everything

Roman55 [17]

I don’t really understand for question 11 to 13

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3 years ago

Find 5 solutions to the question.<br><br> Y=-1.5x+2

Black_prince [1.1K]

Answer:

<em>☆</em><em><</em><em> </em><em><u>《</u></em><em><u>HOPE IT WILL HELP YOU</u></em><em>》</em><em>></em><em>☆</em>

Step-by-step explanation:

Y=1.5x+2

<h3><em><u>(</u></em><em><u>x</u></em><em><u>=</u></em><em><u>1</u></em><em><u>)</u></em></h3>

y=1.5 (1) +2

y=1.5+2

y=3.5

<h3><em><u>(</u></em><em><u>x</u></em><em><u>=</u></em><em><u>2</u></em><em><u>)</u></em></h3>

y=1.5(2)+2

y=3+2

y=5

<h3><em><u>(</u></em><em><u>x</u></em><em><u>=</u></em><em><u>3</u></em><em><u>)</u></em></h3>

y=1.5 (3)+2

y=4.5+2

y=6.5

<h3>(x=4)</h3>

y=1.5 (4)+2

y=6+2

y=8

<h3><em><u>(</u></em><em><u>x</u></em><em><u>=</u></em><em><u>5</u></em><em><u>)</u></em></h3>

y=1.5 (5)+2

y=7.5+2

y=9.5

<h2><em><u>please</u></em><em><u> </u></em><em><u>mark my ans as BRAIN</u></em><em><u> </u></em><em><u>LIST</u></em></h2>

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3 years ago

Write an explicit formula for an, the nth term of the sequence 4, -24, 144, ....

nadezda [96]

Answer:

Tn = 4(-6)^n-1

Step-by-step explanation:

Write an explicit formula for an, the nth term of the sequence 4, -24, 144, ....

The sequence is a geometric sequence

Tn = ar^n-1

a is the first term

a = 4

r = -24/4 =144/-24

r = -6

Substitute

Tn = 4(-6)^n-1

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2 years ago

A rock drops from a height of 60m. how long does it take for it to hit the ground?

laila [671]

To solve for the time an object takes to hit the ground, the equation

<em>y</em> <em>= y₀ + v₀t + ½gt²</em>, or just <em>0 = y₀ +½gt²</em> since there is no initial velocity and the final y position is 0 (since it is on the ground). Therefore, <em>t = (−2y₀/g)^½.</em>

(-2*60/-9.8)^½ = 3.50 seconds.

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3 years ago