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2 years ago

5

Select the correct answer.

1 answer:

katen-ka-za [31]2 years ago

6 0

Answer:

3x - 4/2

Step-by-step explanation:

2 result(s) for "f(x) = 4x³ - 10 g(x)

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Log3 a/3 = ??????????????????????????

Naddik [55]

We have that
<span>Log3 a/3
</span>Rewrite log3(a/3) using the change of base <span>formula

we know that
</span>The change of base rule can be used if a and b are greater than 0 and not equal to 1, and x is greater than 0<span>.
</span>so
loga(x)=<span>logb(x)/<span>logb<span>(a)
</span></span></span>Substitute in values for the variables in the change of base <span>formula
</span>
in this problem
b=10
a=3
x=a/3

log3(a/3)=[log (a/3)]/[log (3)]

the answer is
[log (a/3)]/[log (3)]

8 0

3 years ago

Read 2 more answers

14. Molly puts two shapes together to make a new shape. The new shape has 6 sides and 6 vertices. Which two shapes did she use?

olganol [36]

She used two trapezoids.

She put one trapezoid on top and one on the bottom.

The shape she ends up making is a hexagon.

3 0

3 years ago

What is y - 2 = -3 [x-7] written in standard form

Akimi4 [234]

Y=-3x+23

distribute -3, get y alone (add 2 to both sides)

3 0

3 years ago

Solve the system by substitution

Tatiana [17]

Answer:

(x,y) = (-36,6)

Step-by-step explanation:

-6y=x

x+y=-30

x=-6y,

so -6y+y=-30

-5y=-30

y=6

x=-36

Hope this helps pls hit the crown :D

8 0

3 years ago

The total monthly profit for a firm is P(x)=6400x−18x^2− (1/3)x^3−40000 dollars, where x is the number of units sold. A maximum

wlad13 [49]

Answer:

Maximum profits are earned when x = 64 that is when 64 units are sold.

Maximum Profit = P(64) = 2,08,490.666667$

Step-by-step explanation:

We are given the following information: $P(x) = 6400x - 18x^2 - \frac{x^3}{3} - 40000$ , where P(x) is the profit function.

We will use double derivative test to find maximum profit.

Differentiating P(x) with respect to x and equating to zero, we get,

$\displaystyle\frac{d(P(x))}{dx} = 6400 - 36x - x^2$

Equating it to zero we get,

$x^2 + 36x - 6400 = 0$

We use the quadratic formula to find the values of x:

$x = \displaystyle\frac{-b \pm \sqrt{b^2 - 4ac} }{2a}$ , where a, b and c are coefficients of $x^2, x^1 , x^0$ respectively.

Putting these value we get x = -100, 64

Now, again differentiating

$\displaystyle\frac{d^2(P(x))}{dx^2} = -36 - 2x$

At x = 64, $\displaystyle\frac{d^2(P(x))}{dx^2} < 0$

Hence, maxima occurs at x = 64.

Therefore, maximum profits are earned when x = 64 that is when 64 units are sold.

Maximum Profit = P(64) = 2,08,490.666667$

6 0

3 years ago