Distance from P to the x-axis = 2x distance from P to the yz-plane
<span>Distance to the x-axis of a point P=(x,y,z) is (y^2+z^2)^1/2 </span>
<span>Distance to the yz-plane of a point P=(x,y,z) is x </span>
<span>So your equation is: </span>
<span>(y^2+z^2)^1/2 = 2x </span>
<span>=> y^2 + z^2 = 4x^2 </span>
<span>=> y^2 + z^2 - 4x^2 = 0
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Answer:
F
Step-by-step explanation:
1m = 100cm
0.8m = 100*0.8 = 80cm
Answer:
8
Step-by-step explanation:
A scale factor of 4/5 means that each side length or distance is multiplied by 4/5. 10*4/5=8. Hope this helps!
Answer:
1200 in³
Step-by-step explanation:
V= l×w×h
they gave you l×w which is 200.
200×6= 1200
Answer:
![6 \sqrt[3]{5}](https://tex.z-dn.net/?f=6%20%5Csqrt%5B3%5D%7B5%7D)
Step-by-step explanation:
For the problem, ![\sqrt[3]{24} *\sqrt[3]{45}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B24%7D%20%2A%5Csqrt%5B3%5D%7B45%7D)
, use rules for simplifying cube roots. Under the operations of multiplication and division, if the roots have the same index (here it is 3) you can combine them.
![\sqrt[3]{24} *\sqrt[3]{45} = \sqrt[3]{24*45}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B24%7D%20%2A%5Csqrt%5B3%5D%7B45%7D%20%3D%20%5Csqrt%5B3%5D%7B24%2A45%7D)
You can multiply it out completely, however to simplify after you'll need to pull out perfect cubes. Factor 24 and 45 into any perfect cube factors which multiply to each number. If none are there, then prime factors will do. You can group factors together such as 3*3*3 which is 27 and a perfect cube.
![\sqrt[3]{24*45} =\sqrt[3]{3*8*5*3*3} = 6 \sqrt[3]{5}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B24%2A45%7D%20%3D%5Csqrt%5B3%5D%7B3%2A8%2A5%2A3%2A3%7D%20%20%3D%206%20%5Csqrt%5B3%5D%7B5%7D)
