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2 years ago

When the sum of a number and 3 is subtracted from 10 the result is 5 solve om algebraic equation?

Mathematics

1 answer:

german2 years ago

5 0

Answer:

y = 2

Step-by-step explanation:

Algebraic Equation is an equation where alphabets are used to represent numbers.

Solving the above question,

Let the number = y

Therefore,

Sum of the number = y + 3

If it's subtracted from 10 it becomes

10 - ( y + 3 )

The result : 10 - y - 3 = 5

- y = 5 - 10 + 3

- y = -2

Therefore,

y = 2

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Answer:

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Step-by-step explanation:

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3 years ago

4x² - 5x + 3y + 6

dusya [7]

Answer:

The coefficient in the first term is 4

The constant is 6

There are 4 terms in this expression

The variable in the third term is y

Step-by-step explanation:

The constant is 6 because it is the only term without a variable, therefore the one term that will stay the same/remain constant.

The first term is 4x^2, the second term is -5x, the third term is 3y, and the fourth term is 6.

The variable in the first term is x^2, therefore the coefficient of x^2 is 4.

8 0

3 years ago

MORE EXA<br>-7x + 11 = 19 - X

Allisa [31]

The answer is x=1.3
You are welcome

4 0

4 years ago

A line segment AB has the coordinates A (2,3) AND B ( 8,11) answer the following questions (1) What is the slope of AB? (2) What

GalinKa [24]

Answer:

(1) The slope of the line segment AB is 1. $\bar 3$

(2) The length of the line segment AB is 10

(3) The coordinates of the midpoint of AB is (5, 7)

(4) The slope of a line perpendicular to the line AB is-0.75

Step-by-step explanation:

The coordinates of the line segment AB are;

A(2, 3) and B(8, 11)

(1) The slope of a line segment is given by the following equation;

$Slope, \, m =\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}$

Where;

(x₁, y₁) and (x₂, y₂) are two points on the line segment

Therefore;

The slope, m, of the line segment AB is given as follows;

A(2, 3) = (x₁, y₁) and B(8, 11) = (x₂, y₂)

$Slope, \, m_{AB} =\dfrac{11-3}{8-2} = \dfrac{8}{6} = 1 \frac{1}{3} = 1.\bar3$

The slope of the line segment AB = 1. $\bar 3$

(2) The length, l, of the line segment AB is given by the following equation;

$l = \sqrt{\left (y_{2}-y_{1} \right )^{2}+\left (x_{2}-x_{1} \right )^{2}}$

Therefore, we have;

$l_{AB} = \sqrt{\left (11-3 \right )^{2}+\left (8-2 \right )^{2}} = \sqrt{64 +36} = 10$

The length of the line segment AB is 10

(3) The coordinates of the midpoint of AB is given as follows;

$Midpoint, M = \left (\dfrac{x_1 + x_2}{2} , \ \dfrac{y_1 + y_2}{2} \right )$

Therefore;

$Midpoint, M_{AB} = \left (\dfrac{2 + 8}{2} , \ \dfrac{3 + 11}{2} \right ) = (5, \ 7)$

The coordinates of the midpoint of AB is (5, 7)

(4) The relationship between the slope, m₁, of a line AB perpendicular to another line DE with slope m₂, is given as follows;

$m_1 = -\dfrac{1}{m_2}$

Therefore, the slope, m₁, of the line perpendicular to the line AB, that has a slope m₂ = 4/3 = 1. $\bar 3$ is given as follows;

$m_1 = -\left (\dfrac{1}{\frac{4}{3} } \right ) = -\dfrac{3}{4} = -0.75$

The slope, m₁, of the line perpendicular to the line AB is m₁ = -0.75.

8 0

3 years ago

The graphs of f(x)=-2x and g(x)=(1/2)^x are shown. what are the solutions to thr equation -2x=(1/2)^x? select each correct answe

sineoko [7]

Answer:

Step-by-step explanation:

hello :

f(x)=-2x and g(x)=(1/2)^x

f(-2)=-2(-2) =4

g(-2)=(1/2)^-2 = 1/2^-2 = 2²=4

4 0

3 years ago