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3 years ago

What is the answer plz

Mathematics

1 answer:

Bumek [7]3 years ago

6 0

Answer:

9 days

Step-by-step explanation:

He sets his watch 12 seconds behind

For every day that passes it falls back another 1 second

So once it is 21 seconds behind all you have to do is subtraction to find the amount of days past

21 - 12 = 9

Since its 12 seconds behind already itll take 9 days to be behind 9 more seconds.

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(2x-7)-(4x^2+6x-3)+(x^2+4)

masha68 [24]

Answer:

$-3x^2-4x$

Step-by-step explanation:

Simplify:

$\left(2x-7\right)-\left(4x^2+6x-3\right)+\left(x^2+4\right)$

$=2x-7-\left(4x^2+6x-3\right)+x^2+4$

Group same factor:

$=-\left(4x^2+6x-3\right)+x^2+2x-7+4$

Add :

$=-\left(4x^2+6x-3\right)+x^2+2x-3$

Apply the distributive law: -(a+b) = -a - b

$-\left(4x^2+6x-3\right)=-4x^2-6x+3$

$=-4x^2-6x+3+x^2+2x-3$

Group same factor:

$=-4x^2+x^2-6x+2x+3-3$

Subtract:

$=-4x^2+x^2-6x+2x$

Add:

$=-3x^2-6x+2x$

Group same factor:

$=-3x^2-4x$

Hence answer = $-3x^2-4x$

~lenvy~

8 0

1 year ago

The length of a rectangle is three times longer than its width. The perimeter of the rectangle is 16 feet. If x represents the w

scoray [572]

Given that x represents the width of the rectangle and that the length of the rectangle is three times longer than the width. Then the length is 3x. The perimeter of a rectangle is given by 2(length + width) = 2(3x + x) = 2(4x) = 8x. The perimeter of the rectangle is 16 feet. Therefore, the required equation is 8x = 16.

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2 years ago

CLEAR HIGHLIGHTING

Tasya [4]

Yikes I think 3 or 6

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2 years ago

Consider that AQRS is similar to ALMN and the measure of ZN is 42°. What is the measure of 2S?

Umnica [9.8K]

Answer:

Step-by-step explanation:

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2 years ago

Maria finds a local gym that advertises 67 training sessions for $2052. Find the cost of 153 training sessions.

Ann [662]

Answer:

$Cost\ of\ 153\ training\ sessions\ =\$4685.9\approx\$4686$

Step-by-step explanation:

$Cost\ of\ 67\ training\ sessions\ =\$2052\\\\Cost\ of\ 1\ training\ sessions\ =\frac{Total\ cost}{Total\ training\ sessions}\\\\Cost\ of\ 1\ training\ sessions\ =\frac{2052}{67}\\\\Cost\ of\ 153\ training\ sessions\ =153\times cost\ of\ 1\ training\ sessions\ \\\\Cost\ of\ 153\ training\ sessions\ =153\times\frac{2052}{67}=4685.9\\\\Cost\ of\ 153\ training\ sessions\ \$4685.9\approx4686$

7 0

2 years ago