Question

You need a 75 % alcohol solution. On hand, you have a 260 mL of a 30% alcohol mixture. You also have 95 % alcohol mixture . How much of the 95% mixture will you need to add to obtain the desired solution? You will need mL of the 95% solution

Answer 1

$30 \: percent \: alcohol \: in \: 260 \: ml \\ alcohol = 0.3 \times 26 0= 78 \: ml$

$c( \gamma ) = \frac{78 + 0.95\gamma }{260 + \gamma } \times 100$

$c( \gamma ) = 75$

$\frac{78 + 0.95\gamma }{260 + \gamma } = 0.75$

$78 + 0.95\gamma = 0.75 \gamma + 195 \\ 0.2 \gamma = 117 \\ \gamma = 585$

$we \: need \: 585 \: ml \: of \: 95% \: alcohol$

Answer 2

Answer:

You will need 585 mL of the 95% solution.

Step-by-step explanation: