Complete question :
How many dimes might he have?
How many coins would he have altogether?
Answer:
11, 12, 13, 14 ;
16, 17, 18, 19
Step-by-step explanation:
Let :
Nickel = n
Dimes = d
Total number of nickels = 5
He has more than 2 times as many dimes as nickels ;
d > 2n
d > 2*5 ; d > 10
He has fewer than 3 times as many dimes as nickels;
d < 3n
d < 3*5 ; d < 15
Meaning he has more than 10 dimes but less than 15.
10 < d < 15
So, d could be ;
11, 12, 13, 14
Number of coins altogether :
11 + 5 = 16
12 + 5 = 17
13 + 5 = 18
14 + 5 = 19
