Complete question :
How many dimes might he have?
How many coins would he have altogether?
Answer:
11, 12, 13, 14 ;
16, 17, 18, 19
Step-by-step explanation:
Let :
Nickel = n
Dimes = d
Total number of nickels = 5
He has more than 2 times as many dimes as nickels ;
d > 2n
d > 2*5 ; d > 10
He has fewer than 3 times as many dimes as nickels;
d < 3n
d < 3*5 ; d < 15
Meaning he has more than 10 dimes but less than 15.
10 < d < 15
So, d could be ;
11, 12, 13, 14
Number of coins altogether :
11 + 5 = 16
12 + 5 = 17
13 + 5 = 18
14 + 5 = 19
117 students
13/100 = X/900
(13 * 900)/100 = 117
Median = 45
We are given the following data set:
21, 23, 76, 47, 55, 135, 45, 30, 17
Median is the number that divides the data into two equal parts.
Formula:
Sorted data:
17, 21, 23, 30, 45, 47, 55, 76, 135
Sample size = 9, which is odd
Median =
The median of given set of numbers is 45.
depends on what the homework is