Someone help me with this pls

What is this in slope intercept form?

Zielflug [23.3K]

Answer:

y=3/2x+2.5

Step-by-step explanation:

7 0

3 years ago

Use synthetic division to solve (4x^3-3x^2+5x+6)/(x+6).what is the quotient

ladessa [460]

Answer:

The quotient= $4x^2-27x+167$ .

Step-by-step explanation:

Given

Dividened= $4x^3-3x^2+5x+6$

Divisor= $x+6$

In synthetic division : Put denomerator is equal to zero.

Put x+6=0

x=-6

Put -6 in division box as a divisor.

Coefficient of x^3=4

Coefficient of x^2=-3

Coefficient of x=5

Constant value=6

Put the coefficient of x^3,x^2,x and constant in descending order of power of x in division problem.

Now ,bring the coefficient of x^3 is 4 straight down .

Now, multiply the numbe -6 in the division box with the number 4 brought down and put the result -24 below the number - 3 of next column.

By adding we get -27 and write result in the bottom of row .

Again ,the number -6 multiply with -27 and put the result=162 below the number of next column.

By adding two number together we get 167 and put the result in the bottom of row.

Again, the number -6 in division box multiply with the number 167 and put the result=1002 below the number of next column.

Adding two number together we get 1008 and write in the bottom of row.

Last number is remainder and then write the remainder in fraction .

In quotient the power of x reduces by 1 from the numertor.

Hence, the quotient = $4x^2-27x+167$

Remainder= $\frac{1008}{x+6}$ .

7 0

3 years ago

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2. Find the slope of each line.

puteri [66]

Answer:

6/2 or 3

Step-by-step explanation:

count the amount it rises and put that over the amount it moves on x axis or the run.

4 0

3 years ago

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Graph the equation. y-4=1/4(x-1)²

Anastaziya [24]

Y-4=1/4*(x-1)²
<span>y=1/4(x-1)²+4
</span><span>the parabola y=1/4x2 with vertex at the point (1;4),the branches up,x=1 is the axis of symmetry intersects the axis of the OY at the point (0;4 1/4)
</span>

4 0

3 years ago

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The ground-state wave function for a particle confined to a one-dimensional box of length L is Ψ=(2/L)^1/2 Sin(πx/L). Suppose th

Hitman42 [59]

Answer:

(a) 4.98x10⁻⁵

(b) 7.89x10⁻⁶

(c) 1.89x10⁻⁴

(d) 0.5

(e) 2.9x10⁻²

Step-by-step explanation:

The probability (P) to find the particle is given by:

$P=\int_{x_{1}}^{x_{2}}(\Psi\cdot \Psi) dx = \int_{x_{1}}^{x_{2}} ((2/L)^{1/2} Sin(\pi x/L))^{2}dx$

$P = \int_{x_{1}}^{x_{2}} (2/L) Sin^{2}(\pi x/L)dx$ (1)

The solution of the intregral of equation (1) is:

$P=\frac{2}{L} [\frac{X}{2} - \frac{Sin(2\pi x/L)}{4\pi /L}]|_{x_{1}}^{x_{2}}$

(a) The probability to find the particle between x = 4.95 nm and 5.05 nm is:

$P=\frac{2}{100} [\frac{X}{2} - \frac{Sin(2\pi x/100)}{4\pi /100}]|_{4.95}^{5.05} = 4.98 \cdot 10^{-5}$

(b) The probability to find the particle between x = 1.95 nm and 2.05 nm is:

$P=\frac{2}{100} [\frac{X}{2} - \frac{Sin(2\pi x/100)}{4\pi /100}]|_{1.95}^{2.05} = 7.89 \cdot 10^{-6}$

(c) The probability to find the particle between x = 9.90 nm and 10.00 nm is:

$P=\frac{2}{100} [\frac{X}{2} - \frac{Sin(2\pi x/100)}{4\pi /100}]|_{9.90}^{10.00} = 1.89 \cdot 10^{-4}$

(d) The probability to find the particle in the right half of the box, that is to say, between x = 0 nm and 50 nm is:

$P=\frac{2}{100} [\frac{X}{2} - \frac{Sin(2\pi x/100)}{4\pi /100}]|_{0}^{50.00} = 0.5$

(e) The probability to find the particle in the central third of the box, that is to say, between x = 0 nm and 100/6 nm is:

$P=\frac{2}{100} [\frac{X}{2} - \frac{Sin(2\pi x/100)}{4\pi /100}]|_{0}^{16.7} = 2.9 \cdot 10^{-2}$

I hope it helps you!

3 0

4 years ago