Question

How many solutions does the system

Answer 1

To solve the system of equations we need to use elimination. But to do that we are required to rewrite the equations in implicit form.

$ax+by+c=0$

So we have,

$3x-y+3=0 \\ -2x-y+3=0$

Then multiply the first equation by 2 on both sides and second equation by 3 on both sides. Resulting with,

$6x-2y+6=0 \\ -6x-3y+9=0$

Adding these two equations eliminates the first term in both since 6x - 6x = 0. Hence,

$-5y+15=0\Longrightarrow y=3$

Now that we know the value of y we can insert it in either one of the equations in the system. I'll pick first one to get x.

$3=3x+3\Longrightarrow 3x=0\Longrightarrow x=0$

So the solution to this system of equation are $\boxed{x=0},\boxed{y=3}$

Hope this helps.

r3t40

Answer 2

Answer:

one solution (0, 3)

Step-by-step explanation:

The left sides of both equations are equal, so you can equate the right sides

3х + 3 = -2х + 3

3х + 2х = 3 - 3

5х = 0

х = 0

Put value of x in equation 1 to find value of y

y = 3x + 3 = 3*0 + 3 = 3

Тhe system of equations has one solution (0, 3)