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dusya [7]
2 years ago
13

He is offered a discount for the first five months. after this period, his rate increases by $8.50 per month. his total cost at

the end of the year is $245.50. paul wrote the following equation represent his plan. 5x + 7(x + 8.50) = 245.50 part a: how much, in total, will paul pay during the five discounted months of his plan? (1 point
Mathematics
1 answer:
kogti [31]2 years ago
5 0

The first five months Paul paid  and in the next seven months he paid 24.

<h3>What is a Discount ?</h3>

Discounts are defined as lowered prices or the sale of an item for less than it would typically cost. The fundamental formula for calculating a discount is to multiply the original price by the given percentage rate in decimal form. We must deduct the discount from the original price to determine the item's sale price. A discount is an amount that is subtracted from the regular price of an item.

Paul represent his plan in the form of equation:

5 x+7(x+8.50)=245.50

Where x  is an amount for the first 5 months that is paid by Paul after the discount and (x+8.50)  is an amount for the next 7 month after discount.

&\Rightarrow \quad 5 x+7 x+59.50=245.50 \\&\Rightarrow \quad 12 x=186 \\&\Rightarrow \quad x=\frac{186}{12} \\&\Rightarrow \quad x=15.50\end{aligned}

For the next 7 month:

(x+8.50)=(15.50+8.50)=\$ 24

Therefore, The first 5 months Paul paid $ 15.50, and in the next 7 months he paid $ 24.

To learn more about discount here:

brainly.com/question/15208981

#SPJ4

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Solve for x: 4 over x plus 4 over quantity x squared minus 9 equals 3 over quantity x minus 3. (2 points) Select one: a. x = -4
Kay [80]

Answer:

<h2>c. x = -4 or x = 9</h2>

Step-by-step explanation:

\dfrac{4}{x}+\dfrac{4}{x^2-9}=\dfrac{3}{x-3}

Domain:

x\neq0\ \wedge\ x^2-9\neq0\ \wedge\ x-3\neq0\\\\x\neq0\ \wedge\ x\neq\pm3

solution:

\dfrac{4}{x}+\dfrac{4}{x^2-3^2}=\dfrac{3}{x-3}

use <em>(a - b)(a + b) = a² - b²</em>

\dfrac{4}{x}+\dfrac{4}{(x-3)(x+3)}=\dfrac{3}{x-3}

multiply both sides by (x - 3) ≠ 0

\dfrac{4(x-3)}{x}+\dfrac{4(x-3)}{(x-3)(x+3)}=\dfrac{3(x-3)}{x-3}

cancel (x - 3)

\dfrac{4(x-3)}{x}+\dfrac{4}{x+3}=3

subtract \frac{4(x-3)}{x} from both sides

\dfrac{4}{x+3}=3-\dfrac{4(x-3)}{x}\\\\\dfrac{4}{x+3}=\dfrac{3x}{x}-\dfrac{(4)(x)+(4)(-3)}{x}\\\\\dfrac{4}{x+3}=\dfrac{3x-\bigg(4x-12\bigg)}{x}\\\\\dfrac{4}{x+3}=\dfrac{3x-4x-(-12)}{x}\\\\\dfrac{4}{x+3}=\dfrac{-x+12}{x}

cross multiply

(4)(x)=(x+3)(-x+12)

use FOIL

4x=(x)(-x)+(x)(12)+(3)(-x)+(3)(12)\\\\4x=-x^2+12x-3x+36

subtract 4x from both sides

0=-x^2+12x-3x+36-4x

combine like terms

0=-x^2+(12x-3x-4x)+36\\\\0=-x^2+5x+36

change the signs

x^2-5x-36=0\\\\x^2-9x+4x-36=0\\\\x(x-9)+4(x-9)=0\\\\(x-9)(x+4)=0

The product is 0 if one of the factors is 0. Therefore:

x-9=0\ \vee\ x+4=0

x-9=0            <em>add 9 to both sides</em>

x=9\in D

x+4=0          <em>subtract 4 from both sides</em>

x=-4\in D

7 0
3 years ago
Use the compound interest formula to compute the total amount accumulated and the interest eamed.
RideAnS [48]

Answer:

$12,137.39

Step-by-step explanation:

Use the Compound Amount formula:

A = P (1 + r/n)^(nt), where r is the interest rate as a decimal fraction, n is the number of times the interest is compounded each year, and t is the number of years.

Here, A = $9000(1 + 0.075/12)^(12*4), or

             =  $9000(1.3486) = $12,137.39

7 0
3 years ago
A lunch menu consists of 4 different kinds of sandwiches, 5 different kinds
dolphi86 [110]
3 choices sandwich soup drink look at all the numbers
8 0
3 years ago
6x44<br> hbgvtfwtydtwftdftwyfdywdwd
Ipatiy [6.2K]

Answer:

264

Step-by-step explanation:

well you could have just used a calculator!

3 0
3 years ago
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DONT PRESS THE LINK ABOVE ! ITS A SCAM
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