Question

1) A 20-foot ladder is placed against a building. If the top of the ladder will lean against the building 4sqrt(7) - f feet high, how far away from the base of the building is the bottom of the ladder located? Include a sketch that shows all known information and clearly shows what you need to findShow all work and give the exact answer

Answer 1

Answer:

12√2.

Step-by-step explanation:

You can do this by the Pythagoras theorem:

20^2 = x^2 + (4sqrt7)^2    where  x is the distance required.

x^2 = 20^2 - (4sqrt7)^2

      = 400 - 112

      =  288

x  = √288

   =  √144 *√2

   =   12√2.