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kykrilka [37]
2 years ago
11

50 points will give brainliest

Mathematics
1 answer:
Yuki888 [10]2 years ago
5 0

The x-coordinates of the vertices of the hyperbola are 11 and -11

<h3>How to determine the x-coordinates?</h3>

The hyperbola is given as:

\frac{x^2}{121} - \frac{y^2}{49} = 1

A hyperbola is represented as:

\frac{x^2}{a^2} - \frac{y^2}{b^2} = 1

Where the coordinate of the vertex is:

Vertex = (±a, 0)

By comparing the above equations, we have:

a^2= 121

Take the square of both sides

a = 11

Substitute 11 for a in Vertex = (±a, 0)

Vertex = (±11, 0)

Hence, the x-coordinates of the vertices of the hyperbola are 11 and -11

Read more about hyperbola at:

brainly.com/question/26250569

#SPJ1

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The value of z score for the history class test of Opal’s test score is negative one (-1).

<h3>What is normally distributed data?</h3>

Normally distributed data is the distribution of probability which is symmetric about the mean.

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The z score for the normal distributed data can be given as,

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Learn more about the normally distributed data here;

brainly.com/question/6587992

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Step-by-step explanation:

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