We'll use Cramer's rule for 2 equations:
ax + by = e
cx + dy = f
5x -3y = 18 a=5 b=-3 e=18
2x + 7y = -1 c=2 d=7 f=-1
denominator determinant (dn) = (a * d) - (c * b) = 5 * 7 - (2 * -3) = 41
x = [(e * d) - (f * b)] / dn
[18 * 7 - (-1 * -3)] / 41 =
123 / 41 = 3
y = [(a * f) - (c * e)] / dn
= (5 * -1) -(2 * 18) / 41 =
-41 / 41 = -1
Source:
1728.com/cramer.htm
Pay attention here because I'm adding an extra letter to our circle to help keep track of the values in our formula. OUTSIDE of the intercepted arc I'm adding the point E. So the major arc is arc BEG and the minor arc is arc BG. The formula then for us is ∠
. We just don't have values for the arcs yet. If the measure of the central angle is 4x+238, then the measure of arcBG is also 4x+238. Around the outside of the circle is 360°. So we will use it in an expression. ArcBEG=360-(4x+238). Fitting that into our formula we have
![2x+146= \frac{1}{2}[(360-4x-238)-(4x+238)]](https://tex.z-dn.net/?f=2x%2B146%3D%20%5Cfrac%7B1%7D%7B2%7D%5B%28360-4x-238%29-%284x%2B238%29%5D%20)
. Doing all the simplifying inside there we have
and
. Multiply both sides by 2 to get rid of the fraction: 4x+292=-8x-116. Combine like terms to get 12x = -408 and divide to solve for x. x = -34. Fourth choice down from the top.
We all know about the bell curve i.e. normal distribution curve. It is centered about the mean and spread equally on each side.
We describe the area of the curve with the help of standard deviations.
With in 1 standard deviation about the mean i.e. from -1 s.d. (left of mean) to +1 s.d. (right of mean), it covers 68% of the total area of curve.
So, the data that falls outside 1 standard deviation of the mean would be equal to (100% - 68%) i.e. 32%.
So, 32% is the final answer.
Answer:
∠6 > ∠3 is TRUE.
Step-by-step explanation:
We know that acute angle is less than 90 degree while obtuse angle is more than 90 degree. By looking at the given angles, we can easily determine which angle is obtuse or acute. then we can decide which angle is bigger to find the answer.
∠10 > ∠7
FALSE;
Because∠10 is acute while ∠7 is obtuse.
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∠6 > ∠3
TRUE;
Because∠3 is acute while ∠6 is obtuse.
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∠9 > ∠11
FALSE;
Because∠9 is acute while ∠11 is obtuse.
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∠8 > ∠11
FALSE;
Because∠8 is acute while ∠11 is obtuse.
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Answer:
A Strawberries generally cost less.
D If the chef pays $6.00 for a pound of fruit, it is most likely cherries.
Step-by-step explanation:
A and D
