Answer:
A.) 6.4 units
Step-by-step explanation:
We can use the Pythagorean theorem to find the length of AB.
If we find the horizontal and vertical distance of A and B, we form a triangle, with leg lengths of 5 and 4.
Now, we just solve using the Pythagorean theorem.
5^2 = 25
4^2 = 16
25 + 16 = 41
sqrt 41 ≈ 6.4 units.
Hope this helps!
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Answer:
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Answer:
The amount of salt required is 0.3685 grams.
Step-by-step explanation:
20.9% of 1 gram of salt is chlorine, which means the grams of chlorine in 1 gram of salt are
![\dfrac{20.9\%}{100\%} *1\: gram = 0.209g\: \text{chlorine}](https://tex.z-dn.net/?f=%5Cdfrac%7B20.9%5C%25%7D%7B100%5C%25%7D%20%2A1%5C%3A%20gram%20%3D%200.209g%5C%3A%20%5Ctext%7Bchlorine%7D)
Now, to make 220 ppm solution, it must be that
![\dfrac{220}{10^6} = \dfrac{y}{350+y},](https://tex.z-dn.net/?f=%5Cdfrac%7B220%7D%7B10%5E6%7D%20%3D%20%5Cdfrac%7By%7D%7B350%2By%7D%2C)
where
is the grams of chlorine required.
We rearrange the equation and solve for ![y:](https://tex.z-dn.net/?f=y%3A)
![220(350+y) = 10^6y](https://tex.z-dn.net/?f=220%28350%2By%29%20%3D%2010%5E6y)
![77000+220y =10^6y](https://tex.z-dn.net/?f=77000%2B220y%20%3D10%5E6y)
![77000 = (10^6-220)y](https://tex.z-dn.net/?f=77000%20%3D%20%2810%5E6-220%29y)
![y = \dfrac{77000}{999780}](https://tex.z-dn.net/?f=y%20%3D%20%5Cdfrac%7B77000%7D%7B999780%7D)
![\boxed{y= 0.07702g}](https://tex.z-dn.net/?f=%5Cboxed%7By%3D%200.07702g%7D)
since 1 gram of salt has 0.209 grams of chlorine, 0.07702g of chlorine corresponds to
![\dfrac{0.07701}{0.209} = 0.3685g {\text{ of salt. }](https://tex.z-dn.net/?f=%5Cdfrac%7B0.07701%7D%7B0.209%7D%20%3D%200.3685g%20%7B%5Ctext%7B%20of%20salt.%20%7D)
Thus the amount of salt required is 0.3685 grams.
Answer: the answer is c
Step-by-step explanation:brainlist ![\left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%262%263%5C%5C4%265%266%5C%5C7%268%269%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
There must be some variables on p or q
If u send those i can help u