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3 years ago

Find a counterexample to show that the conjecture is false. Any number that is divisible by 2 is also divisible by 6.

Mathematics

2 answers:

Anon25 [30]3 years ago

6 0

The answer is A)22 because 22÷6 is a fraction

GREYUIT [131]3 years ago

4 0

So in order to find the counterexample and to prove it, let us do it one by one with the given options above.
A. 22. 22 is divisible by 2 but NOT DIVISIBLE by 6.
B. 18. 18 is divisible by 2 and also by 6.
C. 36. 36 is divisible by 2 and by 6.
D. 12. 12 is divisible by 2 and by 6.
Take note that when we say counterexample, this is the statement that disproves another statement. Therefore, the answer would be option A. 22. Hope that this answer helps.

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The table below shows the numbers of tickets sold at a movie theater on Friday.

kondor19780726 [428]

Answer:

Number of Adult's tickets sold on Saturday = 3,356

Number of Children's tickets sold on Saturday = 2, 928

Total number of tickets sold over these two days is 8,938.

Step-by-step explanation:

Here, the number of tickets sold on FRIDAY:

Adult Ticket sold = 1,678

Children's Tickets sold = 976

So, the total number of tickets sold on Friday

= Sum of ( Adult + Children's ) tickets = 1,678 + 976 = 2,654 .... (1)

The number of tickets sold on SATURDAY:

Adult Ticket sold = 2 times the number of adult tickets sold on Friday

= 1,678 x 2 = 3,356

Children's Tickets sold = 3 times the number of children's tickets sold on Friday.

= 976 x 3 = 2, 928

So, the total number of tickets sold on Saturday

= Sum of ( Adult + Children's ) tickets = 3,356 + 2,928 = 6, 284 .... (2)

Now, the total number of tickets booked in these two days :

Sum of tickets booked on (Friday + Saturday)

= 2,654 + 6, 284 = 8,938

Hence, total number of tickets sold over these two days is 8,938.

6 0

4 years ago

On a map, 1 in.represents 20 mi. Two cities are 3 1/2 in. apart on the map.How far apart are the actual cities

Juli2301 [7.4K]

70 miles apart :)

hope I helped :) If you want work shown comment of this please :)

8 0

3 years ago

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An athlete jumps these 4 distances in a long jump competition. Which jump does NOT round to 4.7 meters?

Ede4ka [16]

The third jump does not round to 4.7 meters

5 0

3 years ago

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Please help me thank you

Hoochie [10]

Answer:

$\large\boxed{\sin2\theta=\dfrac{\sqrt3}{2},\ \cos2\theta=\dfrac{1}{2}}$

Step-by-step explanation:

We know:

$\sin2\theta=2\sin\theta\cos\theta\\\\\cos2\theta=\cos^2\theta-\sin^2\thet$

We have

$\sin\theta=\dfrac{1}{2}$

Use $\sin^2\theta+\cos^2\theta=1$

$\left(\dfrac{1}{2}\right)^2+\cos^2\theta=1\\\\\dfrac{1}{4}+\cos^2\theta=1\qquad\text{subtract}\ \dfrac{1}{4}\ \text{from both sides}\\\\\cos^2\theta=\dfrac{4}{4}-\dfrac{1}{4}\\\\\cos^2\theta=\dfrac{3}{4}\to\cos\theta=\pm\sqrt{\dfrac{3}{4}}\to\cos\theta=\pm\dfrac{\sqrt3}{\sqrt4}\to\cos\theta=\pm\dfrac{\sqrt3}{2}\\\\\theta\in[0^o,\ 90^o],\ \text{therefore all functions have positive values or equal 0.}\\\\\cos\theta=\dfrac{\sqrt3}{2}$

$\sin2\theta=2\left(\dfrac{1}{2}\right)\left(\dfrac{\sqrt3}{2}\right)=\dfrac{\sqrt3}{2}\\\\\cos2\theta=\left(\dfrac{\sqrt3}{2}\right)^2-\left(\dfrac{1}{2}\right)^2=\dfrac{3}{4}-\dfrac{1}{4}=\dfrac{3-1}{4}=\dfrac{2}{4}=\dfrac{1}{2}$

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3 years ago

You are helping a classmate edit this story. Your classmate decides to change the point of view and write the story from the thi

MAXImum [283]

Answer:

Names of the friends should be included.

Step-by-step explanation:

If you don't include the names of the friends people would get easily lost and confused.

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3 years ago

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