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snow_tiger [21]
3 years ago
13

Jenny paid $17 for 2 large boxes of popcorn and 3 large soft drinks. Justin paid $10 for 1 large box of popcorn and 2 large soft

drinks. Which system of equations could be used to find the costs of one large box of popcorn, p, and one large soft drink, s?
A. 2 p + 3 s = 17 p + 2 s = 10
B. 3 p + 2 s = 17 p + s + 10
C. 2 p + 3 x = 17 p + s = 10
D. 2 p + 3 s = 10 p + 2 s = 17
Mathematics
1 answer:
wolverine [178]3 years ago
6 0

2p + 3d = 17

1p + 2d = 10

^

|

3

D is the correct answer

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Answer:

The 99% confidence interval is between 62.36%(lower bound) and 89.64%(upper bound).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

A sample of 65 students from the freshmen class is used and a mean score of 76% correct is obtained.

This means that n = 65, \pi = 0.76

99% confidence level

So \alpha = 0.005, z is the value of Z that has a pvalue of 1 - \frac{0.005}{2} = 0.995, so Z = 2.575.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.76 - 2.575\sqrt{\frac{0.76*0.24}{65}} = 0.6236

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.76 + 2.575\sqrt{\frac{0.76*0.24}{65}} = 0.8964

0.6236*100 = 62.36%

0.8964*100 = 89.64%

The 99% confidence interval is between 62.36%(lower bound) and 89.64%(upper bound).

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3 years ago
Find the greatest common factor of the monomial 46x^5 10x^3
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2 can fit into 10 and 46
and you can take 3 out of 3 and 5
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5000 people attended a football game. 2350 of the people attending supported the home team, while 2650 supported the visiting te
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Answer:

47%

2350 out of 5000=0.47

move the decimal 2 times

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Answer:

4. C. x = 4 or -4

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