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kondaur [170]
1 year ago
6

H(x)=

Mathematics
1 answer:
UNO [17]1 year ago
7 0

The average rate of change of the function over −2 ≤ x ≤ 2 is 1/2

<h3>How to determine the average rate of change?</h3>

The function is given as:

h(x) = \frac 18x^3 - x^2

The interval is given as:

−2 ≤ x ≤ 2

Calculate h(2) and h(-2)

h(2) = \frac 18 * 2^3 - (2)^2

h(2) = -3

h(-2) = \frac 18 * (-2)^3 - (-2)^2

h(-2) = -5

The average rate of change is then calculated as:

m = \frac{h(-2) - h(2)}{-2-2}

This gives

m = \frac{-5 + 3}{-4}

Evaluate

m = 1/2

Hence, the average rate of change of the function over −2 ≤ x ≤ 2 is 1/2

Read more about average rate of change at

brainly.com/question/23715190

#SPJ1

<u>Complete question</u>

h(x) = \frac 18x^3 - x^2

What is the average rate of change of h over the interval −2 ≤ x ≤ 2

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The graph shows the height of a kicked soccer ball f(x), in feet, depending on the distance from the kicker x, in feet

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