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Shalnov [3]
2 years ago
6

Determine if each of the following functions from {a,b, c,d} to itself is one-to-one and/or onto. Check ALL correct answers. (a)

f(a)
Mathematics
1 answer:
Bumek [7]2 years ago
5 0

<u>The answer is . </u><u>one-to-one.</u>

<u></u>

<h3>What is the domain of a set?</h3>
  • The domain is the set of all first elements of ordered pairs (x-coordinates).
  • The range is the set of all second elements of ordered pairs (y-coordinates).
  • Only the elements "used" by the relation or function constitute the range.
  • Domain: all x-values that are to be used (independent values).

(a) The function is onto because a, b, c, and d are members of its codomain. All points are converted into various points, making it a one-to-one relationship. The response is that it is one-to-one and onto ( A and C).

(b) It is onto because a, b, c, and d are members of the function's codomain. All points are converted into various points, making it a one-to-one relationship. The response is that it is one-to-one and onto (A and B).

(C) The element b is not onto since it is not a part of the function's codomain. All points are converted into various points, making it a one-to-one relationship. One-to-one is the right response.

Learn more about domain of a set

brainly.com/question/16129985

#SPJ4

<u>The complete question is -</u>

Determine if each of the following functions from {a,b,c,d} to itself is one-to-one and/or onto.

Check ALL correct answers.

(a) f(a)=d,f(b)=a,f(c)=c,f(d)=b

A. onto.

B. neither one-to-one nor onto.

C. one-to-one.

f(a)=b,f(b)=a,f(c)=c,f(d)=d

A. one-to-one.

B. onto.

C. neither one-to-one nor onto.

f(a)=c,f(b)=d,f(c)=a

A. one-to-one.

B. onto.

C. neither one-to-one nor onto.

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A high school guidance counselor determined the following information regarding students and their likelihood of playing a sport
iogann1982 [59]

Conditional Probability

Given two events A and B (not excluding), the probability that A occurs given that B has occurred is called a <em>conditional probability</em> and is calculated as:

P(A|B)=\frac{P(A\cap B)}{P(B)}

Where P(A∩B) is the probability that A and B occur simultaneously and P(B) is the probability that B occurs.

Now with the given data, we must find the values of the required probabilities.

30% of the students play a sport (S), this means that:

70% of the students don't play a sport (NS).

65% of the students have a job.

Note that there could be students who both play sports and have a job.

Of the 30% of the students who play a sport, 50% have a job. This means that:

15% of the students play a sport and don't have a job

15% of the students play a sport AND have a job

65% - 15% = 50% of the students have a job and don't play a sport

That last number is the numerator of the equation given above:

P(A∩B) = 0.5

The event B corresponds to students that don't play a sport (NS), thus:

P(B) = 0.7

Thus we have:

P(A|B)=\frac{0.5}{0.7}=\frac{5}{7}

The required probability is 5/7 or 0.7143

4 0
1 year ago
Five children have heights of 138cm, 135cm, 140cm, 139cm, and 141cm.
Bess [88]

Answer:

6 cm

Step-by-step explanation:

To find the range take the largest number and subtract the smallest number

The largest number is 141 and the smallest number is 135

141 - 135 = 6 cm

8 0
3 years ago
Anju had 3 (3 / 4) cup of sugar . She used 1 (2 / 3 )cup of sugar to bake a cake . How mush sugar does anju have lift ?
Artist 52 [7]

Answer:

y=\frac{1}{12} cup\ of\ suger

Step-by-step explanation:

From the question we are told that:

Sample size n=3(3/4)=9/12

Amount used x=1(2/3)=2/3

 

Generally the equation for sugar lift y is given as is mathematically given by

 y=n-x

 y=\frac{9}{12} -\frac{2}{3}

 y=\frac{1}{12}

7 0
3 years ago
About what percent is 6,315 pounds of 20,00?
Tasya [4]
31.5749...9...9....9....9....
6 0
3 years ago
Read 2 more answers
Can someone SMART redo these questions I mean I made a seven and I did all I could I need to know what went wrong
adoni [48]
2. 8x -28 = -140
8x -28 + 28 = -140 + 28
8x = -112
8x/8 = -112/8
x = -14

3. -9 + x/3 = -23
-9 + 9 + x/3 = -23 + 9
x/3 = -14
x/3/3 = -14/3
x = -14/3

4. x/-1.5 - 3.5 = -13.5
x/-1.5 - 3.5 + 3.5 = -13.5 + 3.5
x/1.5 = -10
x/-1.5/-1.5= -10/-1.5
x = 20/3

5.-6(x + 3) = -36
-6x - 18 = -36
-6x - 18 + 18 = -36 + 18
-6x = -18
-6x/-6 = -18/-6
x = 3

6. k + 3.7/9.8 = -0.22
k + 3.7/9.8/9.8 = -0.22/9.8
k + 3.7 = -2.156
k + 3.7 - 3.7 = -2.156 - 3.7
k = -5.856

7. 12(x - 6) = -108
12x - 72 = -108
12x - 72 + 72 = -108 + 72
12x = -36
12x/12 = -36/12
x = -3

8. -21.83x - -19.9 = -23.83
-21.83x + 19.9 = -23.83
-21.83x + 19.9 - 19.9 = -23.83 - 19.9
-21.83x = -43.73
-21.83x/-21.83 = -43.73/-21.83
x = 2

9. -10x - 68 + x = 40
-9x - 68 = 40
-9x -68 + 68 = 40 + 68
-9x = 108
-9x/-9 = 108/-9
x = -12

10. -34 - 3x - 2x = 71
-34 - 5x = 71
-34 + 34 - 5x = 71 + 34
-5x = 105
-5x/-5 = 105/-5
x = -21

11. 3x - 77 - 8x = 23
-5x - 77 = 23
-5x - 77 + 77 = 23 + 77
-5x = 100
-5x/-5 = 100/-5
x = -20

12. 3x - 5(2x - 12) = 123
3x - 10x + 60 = 123
-7x + 60 = 123
-7x + 60 - 60 = 123 - 60
-7x = 63
-7x/-7 = 63/-7
x = -9

13. -3x + 6(x + 6) = 15
-3x + 6x + 36 = 15
3x + 36 = 15
3x + 36 - 36 = 15 - 36
3x = -21
3x /3 = -21/3
x = -7

14. 5x + 2(4x - 9) = -174
5x + 8x - 18 = -174
13x - 18 = -174
13x - 18 + 18 = -174 + 18
13x = -156
13x/13 = -156/13
x = -12

15. -3x + 6(5x + 3) = -171
-3x + 30x + 18 = -171
27x + 18 = -171
27x + 18 - 18 = -171 - 18
27x = -189
27x/27 = -189/27
x = -7










5 0
3 years ago
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