Answer:
2.
sinα=√3/(2√7)
cosα=5/(2√7)
tanα=5/√3
cscα=(2√7)/√3
secα=(2√7)/5
*note* you can simplify the above further (by rationalizing them), but I think it's probably fine to leave them as is *
3.) g15.9
4.)25.4
5.) 70.8
6.) 36.4
Step-by-step explanation:
Cot is the inverse of toa so cot= adj/opp
This means the traingle's adjacent side is √3 and its opposite is 5
with this information let's figure out the hypotonouse
√3²+5²=c²
3+25=c²
28=c²
√28=c
√28=2√7
which means the triangle's
opposite= √3
hypotonous= 2√7
Adjacent= 5
With all of this we can just plug in the numbers to find the missing information (where α=angle or theta)
sinα=√3/(2√7)
cosα=5/(2√7)
tanα=5/√3
cscα=(2√7)/√3
secα=(2√7)/5
For this one we have the adjacent and need the opposite
we will use TOA
Tan(25)=x/34
34tan(25)=x
x=15.9
4.) For this one we have the adjacent but need the hypotonouse
we will use CAH
cos(48)=17/x
17/cos(48)=x
x=25.4
5.) for number 5 we have the oppsite and hypotonouse and so we'll use SOH
sin(α)=17/18
α=70.8
6.) For this one we have the opposite and adjacent and so we'll use TOA
Tan(α)=(31/42)
α=36.4
