The parabolic motion is an illustration of a quadratic function
The equation that models that path of the rocket is y = -16/31x^2 + 256/31x - 880/31
<h3>How to model the function?</h3>
Given that:
x stands for time and y stands for height in feet
So, we have the following coordinate points
(x,y) = (5,0), (11,0) and (10,80)
A parabolic motion is represented as:
y =ax^2 + bx + c
At (5,0), we have:
25a + 5b + c = 0
c= -25a - 5b
At (11,0), we have:
121a + 11b + c = 0
Substitute c= -25a - 5b
121a + 11b -25a - 5b = 0
Simpify
96a + 6b = 0
At (10,80), we have:
100a + 10b + c = 80
Substitute c= -25a - 5b
100a + 10b - 25a -5b = 80
75a -5b = 80
Divide through by 5
15a -b = 16
Make b the subject
b = 15a + 16
Substitute b = 15a + 16 in 96a + 6b = 0
96a + 6(15a + 16) = 0
Expand
96a + 90a + 96 = 0
This gives
186a = -96
Solve for a
a = -16/31
Recall that:
b = 15a + 16
So, we have:
b = -15 * 16/31 + 16
b =-240/31 + 16
Take LCM
b =(-240 + 31 * 16)/31
[tex]b =256/31
Also, we have:
c= -25a - 5b
This gives
c= 25*16/31 - 5 * 256/31
Take LCM
c= -880/31
Recall that:
y =ax^2 + bx + c
This gives
y = -16/31x^2 + 256/31x - 880/31
Hence, the equation that models that path of the rocket is y = -16/31x^2 + 256/31x - 880/31
Read more about parabolic motion at:
brainly.com/question/1130127
Answer:
Step-by-step explanation:
For this case we can use the formula for the future value with compound interest given by:
(1)
For this case since the interest is compounded quarterly we have 3 periods each year, since we have 3 quarters in a year.
r represent the rate =0.026
t = 6 represent the number of years
P = 3200 represent the amount invested at the begin
If we apply the formula (1) we got:
So then the balance after 6 years would be approximately 50995 with the conditions provided.
1 m = 1 x 10⁶ μm
1 m² = (1 x 10⁶)² μm²
1 m² = 1 x 10¹² μm²
area = 1.5 / 1 x 10¹² m²
Area = 1.5 x 10⁻¹² m²
Answer:
I think the first one
Step-by-step explanation:
Answer:
number of ways = 120
Step-by-step explanation:
The number of ways five children can pose for a photograph line up in a row is given by the number of permutations of 5 elements in 5 different positions (positions in the line), then
number of ways = number of permutations of 5 elements = 5! = 5 * 4 * 3 * 2 * 1 = 120
Since the first children that occupies the line can be on any of the positions (5 positions) , but then the second one can choose any of the 4 remaining positions (since the first children had already occupied one) , the third can choose 3 ... and so on.
