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Anettt [7]
3 years ago
13

If you can help me, I will mark you brainliest. Also earn 25 pts!!!Suppose that there are two types of tickets to a show: advanc

e and same-day. The combined cost of one advance ticket and one same-day ticket is $ 45 . For one performance, 30 advance tickets and 20 same-day tickets were sold. The total amount paid for the tickets was $ 1150 . What was the price of each kind of ticket?
Mathematics
1 answer:
AVprozaik [17]3 years ago
7 0

Answer:

Advance ticket costs $25

Same-day ticket costs $20

Step-by-step explanation:

Let x = the price of one the advance ticket.

Let y = the price of one same-day ticket.

The combined cost of one advance ticket and one same-day ticket is $ 45. This means

x + y = 45 - - - - - - 1

For one performance, 30 advance tickets and 20 same-day tickets were sold. The total amount paid for the tickets was $ 1150. This means

30x + 20y = 1150 - - - - - - - - -2

From equation 1, x = 45- y

Put x = 45- y in equation 2

30( 45-y) + 20y = 1150

1350 - 30y + 20y = 1150

-10y = 1150-1350

-10y = -200

y = 200/10 = $20

x = 45-y

x =45-20= $25

Advance ticket costs $25

Same-day ticket costs $20

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