How do I solve for x??
2 answers:
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7.
remember
(ab)/(cd)=(a/c)(b/d)
we can split them up
and
(x^m)/(x^n)=x^(m-n)
=
9.
2 to 3
4(x-1)=15
to
4x-1=15
the distribuutive prperty
a(b-c)=ab-ac
what he did was
a(b-c)=ab-c
he did not distribute the 4 to the -1
4(x-1)+3=18
minus 3
4(x-1)=15
distribute 4 to x and -1
4x-4=15
add 4 to both sides
4x=19
divide by 4
x=19/4
remember
(ab)/(cd)=(a/c)(b/d)
we can split them up
and
(x^m)/(x^n)=x^(m-n)
9.
2 to 3
4(x-1)=15
to
4x-1=15
the distribuutive prperty
a(b-c)=ab-ac
what he did was
a(b-c)=ab-c
he did not distribute the 4 to the -1
4(x-1)+3=18
minus 3
4(x-1)=15
distribute 4 to x and -1
4x-4=15
add 4 to both sides
4x=19
divide by 4
x=19/4
