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aksik [14]
3 years ago
10

Rama jumps 2m 30cm long and swathi jumps 2m 60cm in a competition what is the total distance they jumped together ​

Mathematics
1 answer:
Furkat [3]3 years ago
8 0

Answer:

Step-by-step explanation:

2 m 30 cm

2 m 60 cm

+

_________

4m 90cm

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# 15. Q. Find the area of the trapezoid
harina [27]
Answer:
219.96 yd²

Explanation:
The area of the trapezoid can be calculated using the following rule:
Area of trapezoid = \frac{b1 + b2}{2} * h
where:
b1 is the length of the first base
b2 is the length of the second base
h is the height

Now, in the given we have:
b1 = 15.8 yd
b2 = 21.8 yd
h = 11.7 yd

Substitute with the givens in the above equation to get the area as follows:
area = \frac{15.8 + 21.8}{2}  * 11.7 = 219.96 yd^2

Hope this helps :)
7 0
3 years ago
Helpppppp mathhhhhhhhhh
Alex Ar [27]
The final answer will be 14.4
6 0
4 years ago
How many zeros does the function f(x) = 4x11 − 20x7 + 2x3 − 15x + 14 have?
stepan [7]
There are 3 zeros in this function
8 0
4 years ago
Read 2 more answers
Given the sequence below, and that sequence has a domain of n 2 1, find the fifth
solmaris [256]

The fifth term of f(n) = n² - 3 is 22

\texttt{ }

<h3>Further explanation</h3>

Firstly , let us learn about types of sequence in mathematics.

Arithmetic Progression is a sequence of numbers in which each of adjacent numbers have a constant difference.

\boxed{T_n = a + (n-1)d}

\boxed{S_n = \frac{1}{2}n ( 2a + (n-1)d )}

<em>Tn = n-th term of the sequence</em>

<em>Sn = sum of the first n numbers of the sequence</em>

<em>a = the initial term of the sequence</em>

<em>d = common difference between adjacent numbers</em>

\texttt{ }

Geometric Progression is a sequence of numbers in which each of adjacent numbers have a constant ration.

\boxed{T_n = a ~ r^{n-1}}

\boxed{S_n = \frac{a( 1 - r^n ) }{1 - r}}

<em>Tn = n-th term of the sequence</em>

<em>Sn = sum of the first n numbers of the sequence</em>

<em>a = the initial term of the sequence</em>

<em>r = common ratio between adjacent numbers</em>

Let us now tackle the problem!

\texttt{ }

<u>Given:</u>

f(n) = n² - 3

<u>Asked:</u>

f(5) = ?

<u>Solution:</u>

\texttt{for } n \geq 1 :

f(n) = n^2 - 3

f(5) = 5^2 - 3

f(5) = 25 - 3

f(5) = \boxed{22}

\texttt{ }

<h3>Learn more</h3>
  • Geometric Series : brainly.com/question/4520950
  • Arithmetic Progression : brainly.com/question/2966265
  • Geometric Sequence : brainly.com/question/2166405

<h3>Answer details</h3>

Grade: Middle School

Subject: Mathematics

Chapter: Arithmetic and Geometric Series

Keywords: Arithmetic , Geometric , Series , Sequence , Difference , Term

7 0
4 years ago
Two positive numbers have a difference of 13. The larger number is three more than twice the smaller. Find the two numbers.
Y_Kistochka [10]

Step-by-step explanation: Let x be the larger number and let y be the smaller one.

x-y=13

x=2y+3

Now you can substitute x=2y-3 into the first equation.

x-y=13=(2y+3)-y

y+3=13

y=10

x=2y+3=20+3=23. Hope that helped!

4 0
4 years ago
Read 2 more answers
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