Answer:
Multiply it like a normal number.
Step-by-step explanation:
Take the point away in both numbers
line the numbers up and add the zero at the end of 28
multiply
add the decimal point back after solved (3 decimal points)
818
x280
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If the length of a rectangle is a two-digit number with identical digits and the width is 1/10 the length and the perimeter is 2 times the area of the rectangle, what is the the length and the width
Solution:
Let the length of rectangle=x
Width of rectangle=x/10
Perimeter is 2(Length+Width)
= 2(x+x/10)
Area of Rectangle= Length* Width=x*x/10
As, Perimeter=2(Area)
So,2(x+x/10)=2(x*x/10)
Multiplying the equation with 10, we get,
2(10x+x)=2x²
Adding Like terms, 10x+x=11x
2(11x)=2x^2
22x=2x²
2x²-22x=0
2x(x-11)=0
By Zero Product property, either x=0
or, x-11=0
or, x=11
So, Width=x/10=11/10=1.1
Checking:
So, Perimeter=2(Length +Width)=2(11+1.1)=2*(12.1)=24.2
Area=Length*Width=11*1.1=12.1
Hence, Perimeter= 2 Area
As,24.2=2*12.1=24.2
So, Perimeter=2 Area
So, Answer:Length of Rectangle=11 units
Width of Rectangle=1.1 units
Answer:
2i + 7
Step-by-step explanation:
Given
(5 - 2i) + (2 + 4i) ← remove parenthesis
= 5 - 2i + 2 + 4i ← collect like terms
= 2i + 7
Volume of the cone:
V = 3.14 x 3^2 x 9/3 = 84.78
Volume of half sphere on top of cone:
V = (4/3 x 3.14 x 3^3 )/2 = 56.52
Total volume = 56.52 + 84.78 = 141.3 cm^3
A=567 km+900 km
a=1,467 km
b=567 km+169 km
b=736 km
x^2/a^2+y^2/b^2=1
x^2/(1,467)^2+y^2/(736)^2=1
Please, see the graph in the attached graph.
Thanks.
