All categories

2 years ago

Wyatt buys a one-quart bottle of juice for $4.80. How many fluid ounces of juice did Wyatt buy?

Mathematics

2 answers:

lisabon 2012 [21]2 years ago

7 0

Answer:

Step-by-step explanation:

Unit rate per fluid ounce = $0.15

Step-by-step explanation:

Given that:

Cost of one quart bottle of juice = $4.80

We know that:

One quart = 32 ounces

Unit rate is the rate in which two quantities are compared and one of them is one.

Unit rate =

Unit rate = $0.15 per fluid ounce

Hence,

Unit rate per fluid ounce = $0.15

aleksklad [387]2 years ago

5 0

Answer:

Wyatt bought 32 fluid ounces.

Step-by-step explanation:

If Wyatt bought a 1 quart bottle of juice, (which you would need to convert into fluid ounces) but every 0.1 quarts of juice would be 3.2 fluid ounces. And if 0.5 quarts of juice is 16 ounces we could do 16 + 16 (fluid ounces) and we would get 32 fluid ounces in total.

And that's how you get the answer! :)

You might be interested in

Weegy solve the system of equations 2x+3y=40 and -2x+2y=20

butalik [34]

Who's Weggy?

2x + 3y = 40

-2x + 2y = 20

These are set up so we can just add them for the solution:

5y = 60

y = 12

2y-20=2x

x=y-10=2

Answer: x=2, y=12

7 0

3 years ago

Squash and Water are mixed in the ratio 1:5. Marion needs to make cups of juice that are 150ml for a party. She anticipates she

PIT_PIT [208]

You need to add 1 and 5 and get 6
do 150 divided by 6
you get 25

6 0

2 years ago

What’s the radius of the circle?

const2013 [10]

Answer:

153m

Step-by-step explanation:

perimeter of an arc = theta/360 × 2πr

P= 17πm

theta = 20°

17πm= 20/360 × 2 × π × r

153πm = πr

r = 153m

7 0

2 years ago

A plumbers plastic pipe is 4 m long, has an inside diameter of 4.0 cm and an outside diameter of 5.0cm. What is the volume of th

SCORPION-xisa [38]

Answer: $V=0.0028278\ m^3$

Step-by-step explanation:

Given

Length of the pipe $l=4\ m$

Inside diameter of the pipe $d_i=4\ cm$

Outside diameter of the pipe $d_o=5\ cm$

Volume of the pipe

$\Rightarrow V=\dfrac{\pi }{4}[d_o^2-d_i^2]\\\\\text{Insert the values}\\\\\Rightarrow V=\dfrac{\pi}{4}[5^2-4^2]\times 10^{-4}\times 4\\\\\Rightarrow V=28.278\times 10^{-4}\ m^3\\\\\Rightarrow V=0.0028278\ m^3$