I would say d. Hope that helps
Answer:
<h3>Hence required integers are 11 and 13</h3>
Let x an odd positive integer
Then, according to question
x^2 +(x+2)^2=290
2x^2 +4x−286=0
x^2 +2x−143=0
x ^2+13x−11x−143=0
(x+13)(x−11)=0
x=11 as x is positive
Hence required integers are 11 and 13
Step-by-step explanation:
Hope it is helpful....
-11-8-13(-10)
First, multiply since multiplication goes before subtraction according to the order of operations.
-11-8+130
Then add and subtract from left to right.
-11-8= -19
-19+130=111
Final answer: 111
Answer:
x+y=3
Step-by-step explanation:
For an equation to have no solution, their slope needs to be same and y intercept needs to be different,
so in this case where x+y=2
doing simply, x+y=3 makes a set of equation which has no solution, you can take any real value which is not 2
Answer:
y=3x+2
Step-by-step explanation:
dont put 0 because it dont make sense
if you put 0 n the equation, you will not will get the right equation
