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polet [3.4K]
2 years ago
10

Find 2 consecutive odd integers sum of who's square is 290​ pls send fast

Mathematics
1 answer:
ELEN [110]2 years ago
7 0

Answer:

<h3>Hence required integers are 11 and 13</h3>

Let x an odd positive integer

Then, according to question

x^2 +(x+2)^2=290

2x^2 +4x−286=0

x^2 +2x−143=0

x ^2+13x−11x−143=0

(x+13)(x−11)=0

x=11 as x is positive

Hence required integers are 11 and 13

Step-by-step explanation:

Hope it is helpful....

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Five and one half of 2 and one third is what number?
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Given:

Five and one half of 2 and one third.

To find:

The number for the given statement.

Solution:

Five and one half = 5\dfrac{1}{2}

2 and one third = 2\dfrac{1}{3}

The given statement is five and one half of 2 and one third.

Here, the word "of" is used for multiplication.

So, the expression for the given statement is:

5\dfrac{1}{2}\times 2\dfrac{1}{3}

=\dfrac{10+1}{2}\times \dfrac{6+1}{3}

=\dfrac{11}{2}\times \dfrac{7}{3}

=\dfrac{77}{6}

Therefore, the required number is \dfrac{77}{6}.

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Answer + step-by-step explanation:

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<em><u>Hope this helps, if my answer or explanation is wrong  </u></em>

<em><u>feel free to message me in the comments :).</u></em>  

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