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polet [3.4K]
2 years ago
10

Find 2 consecutive odd integers sum of who's square is 290​ pls send fast

Mathematics
1 answer:
ELEN [110]2 years ago
7 0

Answer:

<h3>Hence required integers are 11 and 13</h3>

Let x an odd positive integer

Then, according to question

x^2 +(x+2)^2=290

2x^2 +4x−286=0

x^2 +2x−143=0

x ^2+13x−11x−143=0

(x+13)(x−11)=0

x=11 as x is positive

Hence required integers are 11 and 13

Step-by-step explanation:

Hope it is helpful....

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Alenkinab [10]

Answer:

x + 14.7

Step-by-step explanation:

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3 0
3 years ago
9. Carla has $200 in her bank account.
Firdavs [7]

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Step-by-step explanation:

Step 1: As we can see in graph, money in Carla is decreasing in multiples of 20 can be referred as 20x.

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Step 4: (c) y-intercept is where value of x becomes 0.

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Step 5: (d) Domain : {0,1,2,3,4,5,6,7,8,9,10}

                  Range : {0,1,2,...,200}

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3 years ago
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