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Inessa05 [86]
3 years ago
13

Write an equation in slope-intercept form for a line with m = 3 and includes the point (0, 2).

Mathematics
1 answer:
maxonik [38]3 years ago
7 0

Answer:

y=3x+2

Step-by-step explanation:

dont put  0 because it dont make sense

if you put 0 n the equation, you will not will get the right equation

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In a group of 80 children there are 3 times as many boys as girls how many girls are there
insens350 [35]
80=x+3x
80=4x
20=x

There are 20 girls.
7 0
2 years ago
A 1st degree polynomial function whose graph intercepts the y-axis at 8.
asambeis [7]

Your answer can be anything in the form y = mx+8 where you replace m with any real number.

You start with y = mx+b, and then replace the b with the y intercept 8.

The y intercept is where the polynomial crosses the y axis.

The value of m does not matter. So you could have y = 2x+8 or y = 3x+8 for instance. Replace m with whatever your favorite number is.

4 0
2 years ago
Help please. I did my best to find the answer but...
lorasvet [3.4K]

Answer:

24

Step-by-step explanation:

This a special right triangle with angle measures of 30° 60° 90°

The side length that sees angle measure 30° is represented with a, the one that sees 90° is represented by 2a and the one that sees 60° is represented by a√2

AC sees angle B which has an angle measure of 60

(6√2)×(√2) = 24

4 0
2 years ago
Point A is at (-1, -9) and point M is at (0.5, -2.5).
vladimir2022 [97]

Answer:

Point B is located at point (2, 4)

Step-by-step explanation:

Since point M is at the center, you find the distance from point A and add that to the other side.

| -1 - 0.5 | = | -1.5 | = 1.5

| -9 - -2.5 | = | -6.5 | = 6.5

Now we can add that to point M to find point B

0.5 + 1.5 = 2

-2.5 + 6.5 = 4

Point B should be at (2, 4)

4 0
2 years ago
(ab^2 x -b^4a^3)^2<br><br> What is the answers
Umnica [9.8K]

Answer:

\left(ab^2x-b^4a^3\right)^2:\quad a^2b^4x^2-2a^4b^6x+a^6b^8

Step-by-step explanation:

Given the expression

\left(ab^2\:x\:-b^4a^3\right)^2

solving the expression

\left(ab^2\:x\:-b^4a^3\right)^2

\mathrm{Apply\:Perfect\:Square\:Formula}:\quad \left(a-b\right)^2=a^2-2ab+b^2

a=ab^2x,\:\:b=b^4a^3

so the expression becomes

=\left(ab^2x\right)^2-2ab^2xb^4a^3+\left(b^4a^3\right)^2

=a^2b^4x^2-2a^4b^6x+a^6b^8

Thus,

\left(ab^2x-b^4a^3\right)^2:\quad a^2b^4x^2-2a^4b^6x+a^6b^8

3 0
2 years ago
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