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anzhelika [568]
2 years ago
10

How many triangles are there?

Mathematics
2 answers:
Thepotemich [5.8K]2 years ago
8 0

Answer:

20

Steps-by-step explanation:

sorry mistake

Igoryamba2 years ago
8 0

Answer:

12

Explanation: I just counted them! :) and there was 6 in the middle and on the outside so 6 + 6 = 12! :)

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How is the graph of y = -8x2 - 2 different from the graph of y = -8x2?
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(Answer D)

Step-by-step explanation:

Please use " ^ " to indicate exponentiation:  y = -8x^2 - 2, y = -8x^2

The graph of y = -8x^2 is an inverted parabola with vertex at (0, 0).

That of y = -8x^2 - 2 is the same as above, except that the whole graph has been shifted 2 units down (Answer D).

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Help!! giving brainiest!!
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The school is closest

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Plot the point of the library and measure the distance from the library to each location.

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13/17% of a quantity is equal to what fraction of the quality
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4 0
3 years ago
A Martian couple has children until they have 2 males (sexes of children are independent). Compute the expected number of childr
Ne4ueva [31]

Answer:

a) 6

b) 4

c) 3

Step-by-step explanation:

Let p be the probability of having a female Martian, and of course, 1-p the probability of having a male Martian.

To compute the expected total number of trials before 2 males are born, imagine an experiment simulating the fact that 2 males are born is performed n times.

Let ak be the number of trials performed until 2 males are born in experiment k. That is,

a1= number of trials performed until 2 males are born in experiment 1

a2= number of trials performed until 2 males are born in experiment 2

and so on.

If a1 + a2 + … + an = N

we would expect Np females.  

Since the experiment was performed n times, there 2n males (recall that the experiment stops when 2 males are born).

So we would expect 2n = N(1-p), or

N/n = 2/(1-p)

But N/n is the average number of trials per experiment, that is, the expectation.

<em>We have then that the expected number of trials before 2 males are born is 2/(1-p) where p is the probability of having a female. </em>

a)

Here we have the probability of having a male is half as likely as females. So

1-p = p/2 hence p=2/3

The expected number of trials would be

2/(1-2/3) = 2/(1/3) =6

This means <em>the couple would have 6 children</em>: 4 females (the first 4 trials) and 2 males (the last 2 trials).

b)

Here the probability of having a female = probability of having a male = 1/2

The expected number of trials would be

2/(1/2) = 4

This means<em> the couple would have 4 children</em>: 2 females (the first 2 trials) and 2 males (the last 2 trials).

c)

Here, 1-p = 2p so p=1/3

The expected number of trials would be

2/(1-1/3) = 2/(2/3) = 6/2 =3

This means<em> the couple would have 3 children</em>: 1 female (the first trial) and 2 males (the last 2 trials).

5 0
3 years ago
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