Number of child tickets bought is 20
<h3><u>
Solution:</u></h3>
Given that It cost 5 dollars for a child ticket and 8 dollars for a adult ticket
cost of each child ticket = 5 dollars
cost of each adult ticket = 8 dollars
Let "c" be the number of child tickets bought
Let "a" be the number of adult tickets bought
Total tickets sold were 110 bringing in 820 dollars
<em>Number of child tickets bought + number of adult tickets bought = 110</em>
c + a = 110 ----- eqn 1
<em><u>Also we can frame a equation as:</u></em>
Number of child tickets bought x cost of each child ticket + number of adult tickets bought x cost of each adult ticket = 820

5c + 8a = 820 -------- eqn 2
Let us solve eqn 1 and eqn 2 to find values of "c" and "a"
From eqn 1,
a = 110 - c ------ eqn 3
Substitute eqn 3 in eqn 2
5c + 8(110 - c) = 820
5c + 880 - 8c = 820
-3c = - 60
c = 20
Therefore from eqn 3,
a = 110 - 20 = 90
a = 90
Therefore number of child tickets bought is 20
Answer:
A = 55
Step-by-step explanation:
take the two identical triangles and join them so that you get a rectangle wih sides 5 and 11. now multiply them togeter to get the are of the polynom
Answer:
IH < IG < HG
Step-by-step explanation:
To solve this equation remember that angle measurements correspond with sides. So, the largest angle will be opposite of the longest side and the smallest angle will be opposite of the shortest side.
First, you need to find m<I; do this by subtracting 52 and 45 from 180. This means that m<I=83, making it the largest angle. Therefore, the angles, in order of least to greatest, are <G, <H, <I. So, to find the final answer, find the sides opposite of each of the angles. This means the answer is IH < IG < HG.
It’s non linear and it’s decreasing