The numerical value of the variance a. is negative if the mean is negative. b. is always larger than the numerical value of the
1 answer:
Answer:
Step-by-step explanation:
Variance is the sum of squares of all items x from mean. i.e
Variance =
Being the sum of squares variance can never be negative irrespective of mean being negative.
Std deviation is the square root of variances. This will thus be less than variance if variance >1 other wise std deviation will be bigger than variance.
Hence option d is right.
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Answer:
- sin(x) = 1
- cos(x) = 0
- cot(x) = 0
- csc(x) = 1
- sec(x) = undefined
Step-by-step explanation:
The tangent function can be considered to be the ratio of the sine and cosine functions:
tan(x) = sin(x)/cos(x)
It will be undefined where cos(x) = 0. The values of x where that occurs are odd multiples of π. The smallest such multiple is x=π/2. The value of the sine function there is positive: sin(π/2) = 1.
The corresponding trig function values are ...
tan(x) = undefined (where sin(x) >0)
sin(x) = 1
cos(x) = 0
__
And the reciprocal function values at x=π/2 are ...
cot(x) = 0 . . . . . . 1/tan(x)
csc(x) = 1 . . . . . . .1/sin(x)
sec(x) = undefined . . . . . 1/cos(x)
