Question

8. A can do a piece of work in 16 days, B in 10 days. A and B work at it together for 6 days and then C finishes it in 3 days. In how many days could C have done it alone? (a) 120 days (c) 140 days (b) 130 days (d) 150 days​

Answer 1

Answer: 120 days

Step-by-step explanation:

A can complete it in 16 days.

=100/16 =6.25%/day.

B has ten days to do it.

10% every day is equal to 100/10.

So they would each contribute 16.25 percent per day as a group.

then for six days,

16.25*6 =97.50percent

97.50% of the work has been finished, in other words.

The amount of work left is now 100-97.5 = 2.5.

C finishes up the remaining job in 3 days

3.5% in 3 days, to be exact.

Consequently, he will finish his entire project in 120 days.

[2.5 * 40 = 100 percent; 40 * 3 = 120 days]