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Gwar [14]
1 year ago
11

8. A can do a piece of work in 16 days, B in 10 days. A and B work at it together for 6 days and then C finishes it in 3 days. I

n how many days could C have done it alone? (a) 120 days (c) 140 days (b) 130 days (d) 150 days​
Mathematics
1 answer:
cupoosta [38]1 year ago
8 0

Answer: 120 days

Step-by-step explanation:

A can complete it in 16 days.

=100/16 =6.25%/day.

B has ten days to do it.

10% every day is equal to 100/10.

So they would each contribute 16.25 percent per day as a group.

then for six days,

16.25*6 =97.50percent

97.50% of the work has been finished, in other words.

The amount of work left is now 100-97.5 = 2.5.

C finishes up the remaining job in 3 days

3.5% in 3 days, to be exact.

Consequently, he will finish his entire project in 120 days.

[2.5 * 40 = 100 percent; 40 * 3 = 120 days]

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Answer:

5.7 units

Step-by-step explanation:

The distance from point P to QS is the distance from point P (1, 1) to the point of interception R(-3, 5).

Use distance formula to calculate distance between P and R:

PR = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Let,

P (1, 1) = (x_1, y_1)

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Plug in the values into the formula.

PR = \sqrt{(-3 - 1)^2 + (5 - 1)^2}

PR = \sqrt{(-4)^2 + (4)^2}

PR = \sqrt{16 + 16}

PR = \sqrt{32}

PR = 5.7 units (to nearest tenth)

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A rectangular prism is 9.8 inches long, 20 inches wide, and 5 inches high. what is the surface area of the rectangular prism?
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