Answer: answer is in picture. :)
Step-by-step explanation:
You have to find the discriminat b^2 -4ac
If it is > 0, the function has two real solutions
if it is = 0, the function has one real solution
if it is <0, the function has no real solution
6^2 - 4(7)(3) = 36 - 84 = - 48
Answer c. no solution
Answer:
1. x = ±9
2. 
3. 12 and -12.
4. Antoine is incorrect. There exists two solutions x=5 and x= -5.
Step-by-step explanation:
According to the questions,
Problem 1. 
i.e. 
i.e. x = ±9.
Problem 2. 
i.e. 
i.e. 
i.e.
Problem 3. [tex]f(x)=x^{2}-144[tex]
To find the roots, we take, [tex]x^{2}-144=0[tex] i.e. [tex]x^{2}=144[tex] i.e. x = ±12.
Thus, the options are 12 and -12.
Problem 4. We have [tex]f(x)=x^{2}+25[tex]
For the roots, we take, [tex]x^{2}+25=0[tex] i.e. [tex]x^{2}=25[tex] i.e. x = ±5.
Thus, Antoine is not correct and two solutions namely x=5 and x= -5 exists.
Answer:
4/3 or 1 1/3
Step-by-step explanation:
So if y = 6, when x = 2/3. Then, x would equal 1 and 1/3, because 12 is twice the amount of 6, so you'd also multiply 2/3 by 2.
(To multiply a whole number by a fraction, first multiply the whole number by the numerator and then divide that by the denominator. For example: 2 × 2 = 4, since you can't really divide 4 by 3 it would stay as is, but you can turn it to a mixed number. 4/3 is the same as 1 whole and an extra 1/3, or in other words 1 1/3).
Hope this helped :)
