Answer:
9.42478
Step-by-step explanation:
The distance from Humood's house to the school is 500m
<h3>How to determine the distance from Humood's house to the school?</h3>
The given parameters are:
Humood's house is (-5,7)
The school is (3,1)
The distance between both points is calculated using
Substitute the known values in the above equation
Evaluate
d = 10
Each unit in the graph is 50m.
So, we have
Distance =10 * 50m
Evaluate the product
Distance = 500m
Hence, the distance from Humood's house to the school is 500m
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Answer:
81 x y^5
Step-by-step explanation:
Simplify the following:
9×3×3 x y^4 y
3×3 = 9:
9×9 x y^4 y
9 x y^4×9 y = 9×9 x y^(4 + 1):
9×9 x y^(4 + 1)
4 + 1 = 5:
9×9 x y^5
9×9 = 81:
Answer: 81 x y^5
Answer:
The answers are A, B, C, F