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2 years ago

To find the quotient of 3 divided by one-sixtto find the quotient three-fourths divided by one-eighth,h, multiply 3 by

Mathematics

1 answer:

ollegr [7]2 years ago

4 0

The quotient of 3 by 1/ 6 and that of 3/4 by 1/ 8 is 1/2 and 4 respectively

<h3>How to find the quotient</h3>

From the given equation, we have to find

= 3/4 ÷ 1/8

First , we take the denominator of the second fraction to be the numerator, we have

$\frac{3}{4} \times \frac{8}{1}$

Multiply through

$\frac{24}{4}$

$6$

To find the quotient of 3 by 1/6

$3 \times \frac{1}{6}$

$\frac{3}{6}$

$\frac{1}{2}$

Thus, the quotient of 3 by 1/ 6 and that of 3/4 by 1/ 8 is 1/2 and 4 respectively

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Find the triangle's area. Drawing not to scale.

jonny [76]

Answer:

924

Step-by-step explanation:

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3 years ago

Help me please for brainliest!

UkoKoshka [18]

Answer:

1)option b

2)option a

Step-by-step explanation:

1) circumference = 62.8 in

=> 2πr= 62.8

=> r= 62.8/(2×3.14)= 10 in

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7 0

3 years ago

Read 2 more answers

The average age of 4 children is 15 yrs . if the ages of their parents are added , their average age is 25 .find the age of thei

WITCHER [35]

The age of the father is 57 years old

<h3>Calculating mean of a population</h3>

Total age = Average age x Population

Average of the four children = 15

Population = 4

Total age of the four children = 15 x 4

Total age of the four children = 60 years

If the parents are added:

Population = 6

Average age = 25

Total age = 25 x 6

Total age = 150 years

Total age of the parents = 150 - 60

Total age of the parents = 110 years

The father is 4 years older than his wife

Let the age of the father be x

The age of the wife = x - 4

x + x - 4 = 110

2x = 114

x = 114/2

x = 57

Therefore, the age of the father is 57 years old

Learn more on The mean of numbers here: brainly.com/question/20118982

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6 0

2 years ago

Find an equation for the perpendicular Bisector of the line segment whose endpoints are (-9,-8) and (7,-4

Alina [70]

equation for the perpendicular Bisector of the line segment whose endpoints are (-9,-8) and (7,-4)

Perpendicular bisector lies at the midpoint of a line

Lets find mid point of (-9,-8) and (7,-4)

midpoint formula is

$\frac{x_1+x_2}{2} ,\frac{y_1+y_2}{2}$

$\frac{-9+7}{2} ,\frac{-8+-4}{2}$

midpoint is (-1, -6)

Now find the slope of the given line

(-9,-8) and (7,-4)

$slope = \frac{y2-y1}{x2-x1} = \frac{-4-(-8)}{7-(-9)}$

$slope = \frac{-4+8}{7+9}= \frac{4}{16} =\frac{1}{4}$

Slope of perpendicular line is negative reciprocal of slope of given line

So slope of perpendicular line is -4

slope = -4 and midpoint is (-1,-6)

y - y1 = m(x-x1)

y - (-6) = -4(x-(-1))

y + 6 = -4(x+1)

y + 6 = -4x -4

Subtract 6 on both sides

y = -4x -4-6

y= -4x -10

equation for the perpendicular Bisector y = -4x - 10

3 0

3 years ago