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natta225 [31]
3 years ago
10

Brainiest to whoever right

Mathematics
1 answer:
Ghella [55]3 years ago
3 0

Answer:

80%

Step-by-step explanation:

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Which is enough information to prove that s is parallel to T? Help faaast first answer gets brainliest!!!!
sdas [7]

Answer:

the answer you picked in the pictures is the correct one

6 0
3 years ago
This can open up new areas to explore if we change those assumptions. For example, both of our proofs that the measures of the a
Fynjy0 [20]

Answer:

this makes no sense can u simplify it in the comments and i'll answer there pls

7 0
3 years ago
Why is it necessary to use the absolute value of the difference when finding the distance on a number line, but not necessary wh
padilas [110]
Remember that the distance on a number line is given by the formula: d=|x_{2}-x_{1}|
where 
d is the distance between the points. 
x_{2} is the second point in the number line.  
x_{1} is the first point in the number line.
Now, suppose we are trying to find the distance between the points -1 and -5; our first point is -1, so x_{1}=-1, and our second point is -5, so x_{2}=-5. Suppose we are going to find the distance between the two point without using absolute value:
d=x_{2}-x_{1}
d=-5-(-1)
d=-5+1
d=-4
Look what we have here, a negative distance! Since distances cannot be negative, we must use absolute value to always get postie distances between two point on a umber line:
d=|x_{2}-x_{1}|
d=|-5-(-1)|
d=|-5+1|
d=|-4|
d=4 

Now, the distance between two coordinates on a plane is given by the formula: d= \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}
where
d is the distance between the two coordinates
(x_{1},y_{2}) are the coordinates of the first point
(x_{2},y_{2}) are the coordinates of the second point 
Notice that (x_{2}-x_{1})^2 and (y_{2}-y_{1})^2 are squared, so it doesn't matter if we get a negative distance because a negative number raised to an even power (like 2) is always positive; therefore we don't need absolute value in this case because we won't ever get a negative distance. 


7 0
3 years ago
If anyone has a graphing calculator with them and can help me do these two problems<br> Algebra 1
katrin2010 [14]

Answer:

3a) y = -0.1x +26000

3b) $16500

4a) y = 8.2x - 16451.27

4b) 79.93

Step-by-step explanation:

3a) y = -0.1x +26000

3b) If the odometer reads 95000 we need to plug in that value for x: y = -0.1(95000) + 26000 = $16500

4a) y = 8.2x - 16451.27

4b) To estimate the number the rabbits in the year 2016, we need to plug in that value for x: y = 8.2(2016) - 16451.27 = 79.93 = 80 rabbits

5 0
3 years ago
Sketch the graph of y=x^2-4x+3
NISA [10]

Answer:

see attached graph

Step-by-step explanation:

Given equation:  y=x^2-4x+3

Standard form of a quadratic equation: y=ax^2+bx+c

where c is the y-intercept

If a > 0 then the parabola opens upwards.

If a < 0 then the parabola opens downwards.

Therefore, the y-intercept of the graph is (0, 3)

To find the x-intercepts, factor the equation:

       y=x^2-4x+3

\implies y=x^2-x-3x+3

\implies y=x(x-1)-3(x-1)

\implies y=(x-3)(x-1)

Therefore, the x-intercepts of the graph are (3, 0) and (1, 0)

To determine the vertex, differentiate the equation:

\implies \dfrac{dy}{dx}=2x-4

Set to zero and solve for x:

2x-4=0 \implies x=2

Substitute x=2 into the original equation and solve for y:

\implies y=(2)^2-4(2)+3=-1

Therefore, the vertex (or turning point) is at (2, -1)

8 0
3 years ago
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