Answer:
Option a is correct -- 
Step-by-step explanation:
If we put infinity directly into the expression we get ∞ + ∞ expression. In order to circumvent it we divide both numerator and denominator with the greatest exponent.

Divide each term by n³


R = (p,p)
S = (p,0)
Since the shape is a square, each side should have the same length, <em>P</em>.
Answer:
While it is a linear equation, it is not a linear function. This is because it is shown to have infinite numbers of y-values instead of being paired up with only one.
2+1+1.5=x
=> ratio of chopped celery=X/2x100%
you could find others, right?
Answer:
25√2
For the opposite side, the hypotenuse, a rhombus is always divided by a angle bisector. Therefore you use the 45-45-90 theorem