Question

Triangle ABC is a non-right triangle with Angle C = 117, a = 12, and b = 18. Find Angle B to the nearest tenth.

Answer 1

Using the law of cosines and sines, the measure of angle B is: 38.4°.

What is the Law of Cosines and Sines?

Law of cosines is: c = √[a² + b² ﹣ 2ab(cos C)]

Law of sines is: sin A/a = sin B/b = sin C/c

Use the law of cosines to find c:

c = √[12² + 18² ﹣ 2(12)(18)(cos 117)]

c ≈ 25.8

Use the law of sines to find angle B:

sin B/b = sin C/c

sin B/18 = sin 117/25.8

sin B = (sin 117 × 18)/25.8

sin B = 0.6216

B = sin^(-1)(0.6216)

B = 38.4°

Learn more about the law of cosines on:

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