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strojnjashka [21]
2 years ago
10

Triangle ABC is a non-right triangle with Angle C = 117, a = 12, and b = 18. Find Angle B to the nearest tenth.

Mathematics
1 answer:
qwelly [4]2 years ago
5 0

Using the law of cosines and sines, the measure of angle B is: 38.4°.

<h3>What is the Law of Cosines and Sines?</h3>

Law of cosines is: c = √[a² + b² ﹣ 2ab(cos C)]

Law of sines is: sin A/a = sin B/b = sin C/c

Use the law of cosines to find c:

c = √[12² + 18² ﹣ 2(12)(18)(cos 117)]

c ≈ 25.8

Use the law of sines to find angle B:

sin B/b = sin C/c

sin B/18 = sin 117/25.8

sin B = (sin 117 × 18)/25.8

sin B = 0.6216

B = sin^(-1)(0.6216)

B = 38.4°

Learn more about the law of cosines on:

brainly.com/question/23720007

#SPJ1

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Step-by-step explanation:

Hi there!

We are given (x+5)(x-5) and we want to find their product.

As these are binomials, we can multiply them using FOIL, which is First, Outer, Inner, Last

So let's start with the firsts, which would be (x+5)(x-5), or the 2 x's; x*x=x²

Next, let's do the outers, which would be (x+5)(x-5); x * -5 = -5x

Now the inners; (x+5)(x-5); 5 * x = 5x
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We can combine the 5x and -5x together to become x²-25

So the answer is x²-25, which is a difference of squares expression (if we have (a-b)(a+b), then the result is a²-b²).

Hope this helps! :)

See more on the difference of squares here: brainly.com/question/16085851

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