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azamat
2 years ago
11

Someone help pls, its urgent! ASAP!!! (Geometry) “Complete the proofs”

Mathematics
1 answer:
Orlov [11]2 years ago
3 0

<u>Question 11</u>

1) \overline{BA} \cong \overline{FA}, \angle 1 \cong \angle 2 (given)

2) \angle A \cong \angle A (reflexive property)

3) \triangle AEB \cong \triangle ACF (ASA)

4) \overline{AC} \cong \overline{AE} (CPCTC)

<u>Question 12</u>

1) Isosceles \triangle ACD with \overline{AC} \cong \overline{AD}, \overline{BC} \cong \overline{ED} (given)

2) \angle ACD \cong \angle ADC (angles opposite congruent sides in a triangle are congruent)

3) \angle ACB and \angle ACD are supplementary. \angle ADC and \angle ADE are supplementary (angles that form a linear pair are supplementary)

4) \angle ACB \cong \angle ADE (supplements of congruent angles are congruent)

5) \triangle ABC \cong \triangle AED (SAS)

6) \overline{AB} \cong \overline{AE} (CPCTC)

7) \triangle ABE is an isosceles triangle (a triangle with two congruent sides is isosceles)

<em>Note: I changed the names of the segments in Question 11 because of the word filter.</em>

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4 years ago
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vladimir2022 [97]
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Call B, the measure of the angle CBA

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=> B = arc cos (1/3) ≈ 70.5°

I will calculate other measures for you, trying to cover the most common ratios: sine, cosine, tangent

1) (segment CA)^2 + (segment BC)^2 = (hypotenuse)^2

=> (segment CA )^2 = (hypotenuse)^2 - (segment BC)^2 = 9^2 - 3^2 = 81 - 9 = 72

=> segment CA = √72 = 6√2

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