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azamat
1 year ago
11

Someone help pls, its urgent! ASAP!!! (Geometry) “Complete the proofs”

Mathematics
1 answer:
Orlov [11]1 year ago
3 0

<u>Question 11</u>

1) \overline{BA} \cong \overline{FA}, \angle 1 \cong \angle 2 (given)

2) \angle A \cong \angle A (reflexive property)

3) \triangle AEB \cong \triangle ACF (ASA)

4) \overline{AC} \cong \overline{AE} (CPCTC)

<u>Question 12</u>

1) Isosceles \triangle ACD with \overline{AC} \cong \overline{AD}, \overline{BC} \cong \overline{ED} (given)

2) \angle ACD \cong \angle ADC (angles opposite congruent sides in a triangle are congruent)

3) \angle ACB and \angle ACD are supplementary. \angle ADC and \angle ADE are supplementary (angles that form a linear pair are supplementary)

4) \angle ACB \cong \angle ADE (supplements of congruent angles are congruent)

5) \triangle ABC \cong \triangle AED (SAS)

6) \overline{AB} \cong \overline{AE} (CPCTC)

7) \triangle ABE is an isosceles triangle (a triangle with two congruent sides is isosceles)

<em>Note: I changed the names of the segments in Question 11 because of the word filter.</em>

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Answer:

480,700 sets (first choice)

Step-by-step explanation:

If all 25 questions are different,

When order of selection counts:

P(25,7)

= 25!/(25-7)!

= 15511210043330985984000000/6402373705728000

= 2422728000

When order of selection does not count count:

C(25,7)

=25!/(7!*(25-7)!)

=15511210043330985984000000/(6402373705728000*5040)

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Hope this helps, have a nice day.

6 0
3 years ago
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Veronika [31]

Answer:

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Step-by-step explanation:

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2 years ago
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3 years ago
Write an equation of the line that passes through 3,1 and 0,10
elena-14-01-66 [18.8K]

Answer:y = -3x + 10

Step-by-step explanation:

To find an equation of a line that passes through two points, we have to first find the slope between the two equation. We can do this by using the slope formula:

where (x₁, y₁) and (x₂, y₂) are the two points that we are finding the slope between.

Lets make (x₁, y₁) equal to (0, 10) and (x₂, y₂) equal to (3, 1). Now we plug them into the slope formula:

So the slope between the two points is -3.

From here, I would normally take one of the points given to us and plug in the point and slope into the point-slope form of a line and then simplify until we get it in slope-intercept form. But if you look carefully, the y-intercept is given to us as the point (0, 10). So we now know that the y-intercept of the line is 10. We can now take the y-intercept and the slope and plug it into the slope-intercept form of a line to get out equation:

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2 years ago
Find the volume and area for the objects shown and answer Question
klio [65]

Step-by-step explanation:

You must write formulas regarding the volume and surface area of ​​the given solids.

\bold{\#1\ Rectangular\ prism:}\\\\V=lwh\\SA=2lw+2lh+2wh=2(lw+lh+wh)\\\\\bold{\#2\ Cylinder:}\\\\V=\pi r^2h\\SA=2\pi r^2+2\pi rh=2\pir(r+h)\\\\\bold{\#3\ Sphere:}\\\\V=\dfrac{4}{3}\pi r^3\\SA=4\pi r^2

\bold{\#4\ Cone:}\\\\V=\dfrac{1}{3}\pi r^2h\\\\\text{we need calculate the length of a slant length}\ l\\\text{use the Pythagorean theorem:}\\\\l^2=r^2+h^2\to l=\sqrt{r^2+h^2}\\\\SA=\pi r^2+\pi rl=\pi r^2+\pi r\sqrt{r^2+h^2}=\pi r(r+\sqrt{r^2+h^2})\\\\\bold{\#5\ Rectangular\ Pyramid:}\\\\V=\dfrac{1}{3}lwh\\\\

\\\text{we need to calculate the height of two different side walls}\ h_1\ \text{and}\ h_2\\\text{use the Pythagorean theorem:}\\\\h_1^2=\left(\dfrac{l}{2}\right)^2+h^2\to h_1=\sqrt{\left(\dfrac{l}{2}\right)^2+h^2}=\sqrt{\dfrac{l^2}{4}+h^2}=\sqrt{\dfrac{l^2}{4}+\dfrac{4h^2}{4}}\\\\h_1=\sqrt{\dfrac{l^2+4h^2}{4}}=\dfrac{\sqrt{l^2+4h^2}}{\sqrt4}=\dfrac{\sqrt{l^2+4h^2}}{2}

\\\\h_2^2=\left(\dfrac{w}{2}\right)^2+h^2\to h_2=\sqrt{\left(\dfrac{w}{2}\right)^2+h^2}=\sqrt{\dfrac{w^2}{4}+h^2}=\sqrt{\dfrac{w^2}{4}+\dfrac{4h^2}{4}}\\\\h_2=\sqrt{\dfrac{w^2+4h^2}{4}}=\dfrac{\sqrt{w^2+4h^2}}{\sqrt4}=\dfrac{\sqrt{w^2+4h^2}}{2}

SA=lw+2\cdot\dfrac{lh_1}{2}+2\cdot\dfrac{wh_2}{2}\\\\SA=lw+2\!\!\!\!\diagup\cdot\dfrac{l\cdot\frac{\sqrt{l^2+4h^2}}{2}}{2\!\!\!\!\diagup}+2\!\!\!\!\diagup\cdot\dfrac{w\cdot\frac{\sqrt{w^2+4h^2}}{2}}{2\!\!\!\!\diagup}\\\\SA=lw+\dfrac{l\sqrt{l^2+4h^2}}{2}+\dfrac{w\sqrt{w^2+4h^2}}{2}\\\\SA=\dfrac{2lw}{2}+\dfrac{l\sqrt{l^2+4h^2}}{2}+\dfrac{w\sqrt{w^2+4h^2}}{2}\\\\SA=\dfrac{2lw+l\sqrt{l^2+4h^2}+w\sqrt{w^2+4h^2}}{2}

6 0
2 years ago
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