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valkas [14]
3 years ago
6

Problem 3

Mathematics
2 answers:
Neko [114]3 years ago
4 0

Answer:

Mathpapa

Step-by-step explanation:

Ilia_Sergeevich [38]3 years ago
3 0

Problem 1 Answer: x=10

<u>Simplify both sides of the equation</u>

<u></u>(2)(x)+(2)(-3)=14(Distribute)<u></u>

<u></u>2x+-6=14<u></u>

<u></u>2x-6=14<u></u>

<u></u>

<u>Add 6 to both sides</u>

2x-6+6=14+6

2x=20

<u></u>

<u>Divide both sides by 2</u>

<u></u>2x/2=20/2<u></u>

<u></u>x=10<u></u>

----------------------------------------------------------------

Problem 2 Answer: x=-7

<u></u>

<u>Simplify both sides of the equation</u>

<u></u>(-5)(x)+(-5)(-1)=40(Distribute)<u></u>

<u></u>-5x+5=40<u></u>

<u></u>

<u>Subtract 5 from both sides</u>

<u></u>-5x+5-5=40-5<u></u>

<u></u>-5x=35<u></u>

<u></u>

<u>Divide both sides by -5</u>

<u></u>-5x/5=35/-5<u></u>

<u></u>x=-7<u></u>

----------------------------------------------------------------

Problem 3 Answer: x=-8

<u></u>

<u>Simplify both sides of the equation</u>

<u></u>(12)(x)+(12)(10)=24(Distribute)<u></u>

<u></u>12x+120=24<u></u>

<u></u>

<u>Subtract 120 from both sides</u>

<u></u>12x+120-120=24-120<u></u>

<u></u>12x=-96<u></u>

<u></u>

<u>Divide both sides by 12</u>

<u></u>12x/12=-96/12<u></u>

<u></u>x=-8<u></u>

----------------------------------------------------------------

Problem 4 Answer: x=-1/2

<u></u>

<u>Move all terms to the left:</u>

<u></u>2(x+6)-(11)=0<u></u>

<u></u>

<u>Multiply parentheses</u>

<u></u>2x+12-11=0<u></u>

<u></u>

<u>Add all the numbers together, and all the variables</u>

<u></u>2x+1=0<u></u>

<u></u>

<u>Move all terms containing x to the left, all other terms to the right</u>

<u></u>2x=-1\\x=-1/2<u></u>

----------------------------------------------------------------

Problem 5 Answer: x = 44

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Solve.
baherus [9]
The correct answer is:  [C]:  " 5 " .
__________________________________________________________
                                →  " a = 5 " .
__________________________________________________________
Explanation:
__________________________________________________________ 

Given:  " a + 1 <span>− 2 = 4 " ; Solve for "a" ; 

4 + 2 = 6 ; 

6 </span>− 1 = 5 ;   →  a = 5 ;

To check our work:

5 + 1 − 2 = ? 4 ?? ;  

5 + 1 = 6 ; 

6 − 2 = 4.  Yes!

So the answer is:  [C]:  " 5 ". 
_________________________________________________________
                          →   " a = 5 " . 
_________________________________________________________
4 0
3 years ago
Is this an example of a horizontal asymptote?
8_murik_8 [283]

Answer:

Step-by-step explanation:

Hi there,

The graph indicated is showing a horizontal asymptote. In fact, it is showing both a horizontal and a <em>vertical </em>asymptote.

To tell which type it is, notice where the graph "shoots off" and almost forms an imaginary straight line in one direction. Using this logic, the horizontal asymptote will be exactly horizontal, parallel to x-axis, and vertical asymptote will be exactly vertical, parallel to y-axis.

With this graph, we notice the horizontal asymptote is at y=0, where the x-axis is. The vertical asymptote is bit more difficult to determine graphically, but can definitely say it is past x=-10. We could determine it if we had the function, but that is not necessary for this question.

Study well, and persevere. If you liked this solution, leave a Thanks or give a rating!

thanks,

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3 years ago
Which of the following parallelograms is NOT similar to the others?<br><br> A<br> B<br> C<br> D
labwork [276]

the answer is D

Step-by-step explanation:

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A=LxW, so W=A/L. Divide 85 by 10.
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Ok so I’m thinking that s = 93 because first I multiply first sides of the equation by -4, which was s-61=32. Then I moved the constant to the right hand side and change its sign which will be s=32+61. After I did all of that I added the numbers together and got 93..... therefore s=93
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2 years ago
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