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3 years ago

5

a teacher says that the top 10% of the class received an A on the last test. the scores were normally distributed with mean 67 a

nd a standard deviation 16. find the minimum score required to get an A. g

1 answer:

12345 [234]3 years ago

5 0

Umm im just here sooooo goodluck oh come one

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Factor x3 ‒ 11x2 ‒ 7x + 77 by grouping. What is the resulting expression?

shepuryov [24]

Answer:

A. $(x^{2}-7)\cdot (x-11)$

Step-by-step explanation:

The third order polynomial is factored herein:

$x^{2}\cdot (x-11) - 7\cdot (x-11)$

$(x^{2}-7)\cdot (x-11)$

Which represents answer A.

6 0

3 years ago

Round your answer to the nearest tenth.

Kruka [31]

Answer:

The value of MB = 8.4

Step-by-step explanation:

We know that the point of intersection of the Medians of a triangle is called the centroid of a triangle.

Thus,

For the given triangle ΔJKL,

The point M is the centroid of the triangle.

We also know that the centroid is 2/3 of the distance from each vertex to the midpoint of the opposite side.

Also, each Median is split into two parts such that the longer part is 2 times the length of the smaller part.

In our case,

The median KB is split into two parts such that the longer part KM is 2 times the length of the smaller part MB.

i.e.

KM = 2 MB

Given KM = 16.8

so substitute KM = 16.8 in the equation KM = 2 MB

16.8 = 2 MB

MB = 16.8/2

MB = 8.4

Therefore, the value of MB = 8.4

7 0

3 years ago

Read 2 more answers

What are the next 3 numbers in this pattern of integers -2, -1, -1, 0, -1, 1, -2

sashaice [31]

Answer:

The next 3 numbers to the given pattern of integers is -2,-1,-1,0,-1,1,-2 are 3,-5,8

Step-by-step explanation:

Given pattern of integers is -2,-1,-1,0,-1,1,-2

To find their next 3 numbers of the given pattern :

Let $a_{1}=-2$

$a_{2}=-1$

$a_{3}=a_{1}-a_{2}$

$=-2-(-1)$

$=-2+1$

Therefore $a_{3}=-1$

$a_{4}=a_{2}-a_{3}$

$=-1-(-1)$

$=-1+1$

Therefore $a_{4}=0$

Similarly we have $a_{5}=-1$ , $a_{6}=1$ , $a_{7}=-2$

The general form to the given pattern is

$a_{n}=a_{n-2}+a_{n-1}$ for $n={\{1,2,3,4,5,6,7,8,9,10}\}$

Therefore to find the $a_{8},a_{9},a_{10}$

Put n=8 in $a_{n}=a_{n-2}-a_{n-1}$

$a_{8}=a_{8-2}-a_{8-1}$

$=a_{6}-a_{7}$

$=1-(-2)$

$a_{8}=3$

Put n=9 in $a_{n}=a_{n-2}-a_{n-1}$

$a_{9}=a_{9-2}-a_{9-1}$

$=a_{7}-a_{8}$

$=-2-(3)$

$a_{9}=-5$

Put n=10 in $a_{n}=a_{n-2}-a_{n-1}$

$a_{10}=a_{10-2}-a_{10-1}$

$=a_{8}-a_{9}$

$=3-(-5)$

$a_{10}=8$

Therefore the next 3 numbers are 3,-5,8

4 0

3 years ago

how is 0.00023 written in scientific notation? a. 23 x 10–5 b. 2.3 x 10–4 c. 2.3 x 104 d. 0.23 x 10–3

Annette [7]

Answer: $2.3\times10^{-4}$

Step-by-step explanation:

We know that Scientific notation is a way to write a very large or a very small number in the product of a decimal form of number [generally between 1 and 10] and powers of ten.

Given number : 0.00023

In scientific notation $0.00023=2.3\times\frac{1}{10000}=2.3\times10^{-4}$

Therefore, In scientific notation $0.00023=2.3\times10^{-4}$

7 0

3 years ago

Read 2 more answers

lbvjy [14]

Answer:

Step-by-step explanation:

2x-10y=10

x=5

y=-1

5x+9y=-9

x= -9/5

y=-1

finding x and y intercept

6 0

3 years ago

Read 2 more answers