Answer:
<em>{9,19,39,79}</em>
Step-by-step explanation:
<u>Recursive Sequences</u>
The recursive sequence can be identified because each term is given as a function of one or more of the previous terms. Being n an integer greater than 1, then:
f(n) = 2f(n-1)+1
f(1) = 4
To find the first four terms of the sequence, we set n to the values {2,3,4,5}
f(2) = 2f(1)+1
Since f(1)=4:
f(2) = 2*4+1
f(2) = 9
f(3) = 2f(2)+1
Since f(2)=9:
f(3) = 2*9+1
f(3) = 19
f(4) = 2f(3)+1
Since f(3)=19:
f(4) = 2*19+1
f(4) = 39
f(5) = 2f(4)+1
Since f(4)=39:
f(5) = 2*39+1
f(5) = 79
x - 2/3 = 5/6
the only step needed is to add 2/3 to 5/6
2/3 + 5/6 = 1 1/2
x = 1 1/2
They give us 2 pieces to the puzzle. Both are positive numbers...x and y.
1.) 1 number is 1 less than twice another number. (x = 2y -1)...and
2.) the sum of their squares is 106. (x^2 + y^2 = 106).
substitute the value for x into the second equation.
(2y-1)^2 + y^2 = 106
(2y-1) (2y-1) + y^2 = 106 (use distributive property)
4y^2 - 2y - 2y + 1 + y^2 = 106 (subtract 106 from both sides)
4y^2 - 2y - 2y + 1 + y^2 - 106 = 106 - 106 (combine like terms)
5y^2 - 4y - 105 = 0 (factor)
(y-5) (5y-21) = 0 (set to 0)
y - 5 = 0
y = 5
substitute the 5 into the equation for y (x = 2(5) - 1)
x = 9 if we square 9, we get 81.
subtracted from 106 we have 25...the square root of 25 is 5.
our answers are 5 and 9.
Answer:
yes
Step-by-step explanation:
yes it is im pretty sure
Answer: 820/17 lol
Step-by-step explanation: coz I juss know
