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lesantik [10]
1 year ago
7

CAB SOMEONE HELP ME ASAP PLS

Mathematics
1 answer:
Anit [1.1K]1 year ago
3 0
A,
The shaded area for yellow is less than 1/5 of a circle, so the answer is the first one.
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What is the difference in the surface area of two cubes, one with edge 15 and one with an edge of 12
Lilit [14]

Remark

A cube has six sides, all of them equal. The formula for 1 side is s^2. The formula for all six = 6s^2.


Step One

Find the surface area of the larger cube.

Area = 6 *s^2

s = 15

Area = 6 *15^2

Area = 6 * 225

Area = 1350


Step Two

Find the area of the smaller cube

Area = 6s^2

Area = 6 * 12^2

Area = 6 * 144

Area = 864


Step Three

Find the difference

Area1 - Area2 = difference

1350 - 864 = 486

The difference is area = 486 units^2 <<<<< Answer


There is a slightly shorter way. Take out the common factor of 6

Difference = 6 * (15^2 - 12^2)

Difference = 6 * (225 - 144)

Difference = 6 * (81)

Difference = 486

6 0
3 years ago
Desmond received a $4.00 tip from a customer who had a $16.00 bill.
olga nikolaevna [1]

Answer:

Step-by-step explanation:0.04

3 0
2 years ago
The equation through the point (5,3) and is parallel the equation y=2/5x+7​
nignag [31]

Answer:

Point - Slope Form: (y - 3) = 0.4(x - 5)

Slope - Intercept Form: y = 0.4x + 1

Step-by-step explanation:

Well if it's parallel, they have the same slope

Slope = 0.4

I'll do it in two forms:

Point - Slope Form: (y - 3) = 0.4(x - 5)

Slope - Intercept Form: y = 0.4x + b

3 = 2 + b

b = 1

y = 0.4x + 1

I might be wrong

3 0
2 years ago
Y+1=3(x−4)<br> Find the Y intercept and the X intercept
vivado [14]
X intercept-(9,2/0)
y intercept-(0,-9)
hope this helps
3 0
3 years ago
Janet deposited $9,600 into an account that pays 4.4 interest, compounded daily. At the end of nine months, how much interest ha
neonofarm [45]

bearing in mind that 9 months is not even a year, but since there are 12 months in a year, then 9 months is really 9/12 years.


\bf ~~~~~~ \stackrel{\textit{daily}}{\textit{Continuously}} \textit{Compounding Interest Earned Amount} \\\\ A=Pe^{rt}\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$9600\\ r=rate\to 4.4\%\to \frac{4.4}{100}\dotfill &0.044\\ t=years\to \frac{9}{12}\dotfill &\frac{3}{4} \end{cases} \\\\\\ A=9600e^{0.044\cdot \frac{3}{4}}\implies A=9600e^{0.033}\implies A\approx 9922.09 \\\\\\


\bf \stackrel{\textit{interest earned}}{9922.09-9600\implies 322.09}

5 0
3 years ago
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