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Natasha2012 [34]
2 years ago
5

Find the missing side of each right triangle (((((Pythagorean’s Theorem))))))))

Mathematics
1 answer:
kaheart [24]2 years ago
7 0

Answer:

3

Step-by-step explanation:

36-27 = 9

\sqrt{9} = 3

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Which values are with in the range of the piecewise defined function?
zepelin [54]

Answer:

y = -6; -3;  0

Step-by-step explanation:

To quickly solve this problem, we can use a graphing tool or a calculator to plot the equation.

Please see the attached image below, to find more information about the graph

The equation is:

f(x)  = 2x+2  , x < -3

f(x) = x, x = -3

f(x) = - x -2 , x > -3

From the graph, we can see that the values are

y = -6; -3;  0

4 0
3 years ago
Read 2 more answers
Determine algebraically whether f(x)=3x-2 and g(x)=(x+2)/3 are inverse functions. Show all work.
Sergio [31]

Answer:

Yes

Step-by-step explanation:

f(x)=3 x-2      

     

y= 3 x-2      

             

x= 3y - 2  

     

3 y -2 = x

3 y -2 + 2 = x + 2

<u>3 y </u> =  <u>x  </u> +  <u>2</u>                                                      

3        3       3

<u>3 y </u> =  <u>x  </u> +  <u>2  </u>                                                    

3        3       3

y =  <u>x </u>  +  <u>2   </u>        replace y with f ^ -1(x)

   <em> </em>  3        3                                            

f ^-1 (x) =    <u>x</u>   +  <u>2 </u>        

                 3       3      

4 0
3 years ago
A sample of 11 students using a Ti-89 calculator averaged 31.5 items identified, with a standard deviation of 8.35. A sample of
lina2011 [118]

Answer:

We reject H₀, with CI = 90 % we can conclude that the mean numbers of times identified with Ti-84 does not exceed that of the Ti-89 by more than 1,80

Step-by-step explanation:

Ti-89 Calculator

Sample mean     x = 31,5

Sample standard deviation   s₂  = 8,35

Sample size        n₂ = 11

Ti-84 Calculator

Sample mean     y = 46,2

Sample standard deviation   s₁  = 9,99

Sample size        n₁ = 12

t(s)  = ( y - x - d ) / √s₁²/n₁ + s₂²/n₂

t(s)  = 12,9 / √(99,8/12) + (69,72/11)

t(s)  = 12,9 / √8,32 + 6,34

t(s)  = 12,9 / 3,83

t(s) = 3,37

Test Hypothesis

Null Hypothesis               H₀      y - x > 1,80

Altenative Hypothesis       Hₐ      y - x ≤ 1,80

We have a t(s) = 3,37

We need to compare with t(c)   critical value for

t(c) α; n₁ +n₂-2            df = 12 +11 -2     df  = 21

If we choose  CI = 95 %    then  α = 5 %   α = 0,05

From t-student table

t(c) = 1,72

t(s) = 3,37

t(s) >t(c)

t(s) is in the rejection region therefore we accept Hₐ with CI = 95 %

8 0
3 years ago
Theo and Kade worked on a school project together. Theo worked on the project 3 fewer hours than Kade did. Altogether, they work
babunello [35]

Let the hours Kade worked = X

Theo would be X - 3 ( 3 less than Kade).

Now you have:

X  + X -3 = 27

Combine like terms:

2x - 3 = 27

Add 3 to each side:

2x = 30

Divide both sides by 2:

x = 15

Kade worked 15 hours.

Theo worked 12 hours.

6 0
3 years ago
Read 2 more answers
15 players two coaches and 21 parents attend this year sports banquet the cost of each meal was $12 +5% sales tax what was the t
Artist 52 [7]

Answer:

$478.80

Step-by-step explanation:

We have been given that 15 players two coaches and 21 parents attend this year sports banquet the cost of each meal was $12 plus 5% sales tax.

First of all, we will find cost of each meal with tax as:

\text{Cost of each meal with tax}=\$12+\$12\times \frac{5}{100}

\text{Cost of each meal with tax}=\$12+\$12\times 0.05

\text{Cost of each meal with tax}=\$12+\$0.6

\text{Cost of each meal with tax}=\$12.6

Now, we will find total persons at the sport banquet as:

\text{Total persons at banquet}=15+2+21

\text{Total persons at banquet}=38

To find the total cost of food for the banquet, we will multiply cost of food for each person by 38.

\text{Total cost of food for the banquet}=\$12.6\times 38

\text{Total cost of food for the banquet}=\$478.8

Therefore, the total cost of food for the banquet is $478.80.

5 0
3 years ago
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