Ask question

Ask question

All categories

Natasha2012 [34]

2 years ago

5

Find the missing side of each right triangle (((((Pythagorean’s Theorem))))))))

1 answer:

kaheart [24]2 years ago

7 0

Answer:

3

Step-by-step explanation:

36-27 = 9

$\sqrt{9} = 3$

You might be interested in

Helena had a balance of $14.48 left on a gift card. She bought a muffin each for her, and five of her friends. The cost of each

Ivenika [448]

She spent $6.12 on the muffins for her and her friends, and she has $8.36 left on her gift card. By multiplying 6 by $1.02, you get the amount she spent, and by subtracting $14.48 by $6.12, I find how much she has left on her gift card.

8 0

2 years ago

PLEASE SHOW ALL THE STEPS THAT YOU USE TO SOLVE THIS PROBLEM

Mademuasel [1]

Answer:

{x = 1 , y=1, z=0

Step-by-step explanation:

Solve the following system:

{-2 x + 2 y + 3 z = 0 | (equation 1)

{-2 x - y + z = -3 | (equation 2)

{2 x + 3 y + 3 z = 5 | (equation 3)

Subtract equation 1 from equation 2:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

{0 x - 3 y - 2 z = -3 | (equation 2)

{2 x + 3 y + 3 z = 5 | (equation 3)

Multiply equation 2 by -1:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

{0 x+3 y + 2 z = 3 | (equation 2)

{2 x + 3 y + 3 z = 5 | (equation 3)

Add equation 1 to equation 3:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

{0 x+3 y + 2 z = 3 | (equation 2)

{0 x+5 y + 6 z = 5 | (equation 3)

Swap equation 2 with equation 3:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

{0 x+5 y + 6 z = 5 | (equation 2)

{0 x+3 y + 2 z = 3 | (equation 3)

Subtract 3/5 × (equation 2) from equation 3:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

{0 x+5 y + 6 z = 5 | (equation 2)

{0 x+0 y - (8 z)/5 = 0 | (equation 3)

Multiply equation 3 by 5/8:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

{0 x+5 y + 6 z = 5 | (equation 2)

{0 x+0 y - z = 0 | (equation 3)

Multiply equation 3 by -1:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

{0 x+5 y + 6 z = 5 | (equation 2)

{0 x+0 y+z = 0 | (equation 3)

Subtract 6 × (equation 3) from equation 2:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

{0 x+5 y+0 z = 5 | (equation 2)

{0 x+0 y+z = 0 | (equation 3)

Divide equation 2 by 5:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

{0 x+y+0 z = 1 | (equation 2)

{0 x+0 y+z = 0 | (equation 3)

Subtract 2 × (equation 2) from equation 1:

{-(2 x) + 0 y+3 z = -2 | (equation 1)

{0 x+y+0 z = 1 | (equation 2)

{0 x+0 y+z = 0 | (equation 3)

Subtract 3 × (equation 3) from equation 1:

{-(2 x)+0 y+0 z = -2 | (equation 1)

{0 x+y+0 z = 1 | (equation 2)

{0 x+0 y+z = 0 | (equation 3)

Divide equation 1 by -2:

{x+0 y+0 z = 1 | (equation 1)

{0 x+y+0 z = 1 | (equation 2)

{0 x+0 y+z = 0 | (equation 3)

Collect results:

Answer: {x = 1 , y=1, z=0

6 0

2 years ago

Your paycheck from work was $304.25. You used some of your earnings to buy an MP3 player for $149. Now it will cost you $1.15 to

Tresset [83]

You could buy 135 MP3 songs.

($304.25 - $149 = $155.25 | $155.25 / 1.15 = 135)

3 0

3 years ago

Read 2 more answers

What the length of a diagonal of a square with perimeter of 16

Vladimir79 [104]

A- the length of the side of a square
P = 16

P = 4a → 4a = 16 |:4 → a = 4

The diagonal of the square: d = a√2

therefore d = 4√2

4 0

3 years ago

A container has 12 and 3/4 cups of lemonade .asher gives each of his classmates 7/8 of a cup of lemonade . He gives away all of

Agata [3.3K]

Asher gave lemonade to 14 students

<em><u>Solution:</u></em>

Given that, A container has 12 and $\frac{3}{4}$ cups of lemonade

Asher gives each of his classmates $\frac{7}{8}$ of a cup of lemonade

To find: Number of classmates received the lemonade

From given question,

Total cups of lemonade = $12\frac{3}{4}$

$\rightarrow 12\frac{3}{4} = \frac{4 \times 12 + 3}{4} = \frac{51}{4}$

cups of lemonade received by each classmate = $\frac{7}{8}$

Thus, number of classmates received the lemonade can be found by dividing total cups of lemonade by cups of lemonade received by each classmate

$\rightarrow \frac{\frac{51}{4}}{\frac{7}{8}}=\frac{51}{4} \times \frac{8}{7}$

$\rightarrow 14.57$

Thus Asher gave lemonade to 14 students

3 0

3 years ago