Answer:
b. 
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Algebra I</u>
- Functions
- Function Notation
- Exponential Rule [Rewrite]:
- Exponential Rule [Root Rewrite]:
<u>
</u>
<u>Calculus</u>
Derivatives
Derivative Notation
Basic Power Rule:
- f(x) = cxⁿ
- f’(x) = c·nxⁿ⁻¹
Derivative Rule [Chain Rule]: ![\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7Bd%7D%7Bdx%7D%5Bf%28g%28x%29%29%5D%20%3Df%27%28g%28x%29%29%20%5Ccdot%20g%27%28x%29)
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify</em>
<em />
<em />
<em />
<u>Step 2: Differentiate</u>
- Rewrite function [Exponential Rule - Root Rewrite]:
![\displaystyle H(x) = [F(x)]^\bigg{\frac{1}{3}}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20H%28x%29%20%3D%20%5BF%28x%29%5D%5E%5Cbigg%7B%5Cfrac%7B1%7D%7B3%7D%7D)
- Chain Rule:
![\displaystyle H'(x) = \frac{d}{dx} \bigg[ [F(x)]^\bigg{\frac{1}{3}} \bigg] \cdot \frac{d}{dx}[F(x)]](https://tex.z-dn.net/?f=%5Cdisplaystyle%20H%27%28x%29%20%3D%20%5Cfrac%7Bd%7D%7Bdx%7D%20%5Cbigg%5B%20%5BF%28x%29%5D%5E%5Cbigg%7B%5Cfrac%7B1%7D%7B3%7D%7D%20%5Cbigg%5D%20%5Ccdot%20%5Cfrac%7Bd%7D%7Bdx%7D%5BF%28x%29%5D)
- Basic Power Rule:
![\displaystyle H'(x) = \frac{1}{3}[F(x)]^\bigg{\frac{1}{3} - 1} \cdot F'(x)](https://tex.z-dn.net/?f=%5Cdisplaystyle%20H%27%28x%29%20%3D%20%5Cfrac%7B1%7D%7B3%7D%5BF%28x%29%5D%5E%5Cbigg%7B%5Cfrac%7B1%7D%7B3%7D%20-%201%7D%20%5Ccdot%20F%27%28x%29)
- Simplify:
![\displaystyle H'(x) = \frac{F'(x)}{3}[F(x)]^\bigg{\frac{-2}{3}}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20H%27%28x%29%20%3D%20%5Cfrac%7BF%27%28x%29%7D%7B3%7D%5BF%28x%29%5D%5E%5Cbigg%7B%5Cfrac%7B-2%7D%7B3%7D%7D)
- Rewrite [Exponential Rule - Rewrite]:
![\displaystyle H'(x) = \frac{F'(x)}{3[F(x)]^\bigg{\frac{2}{3}}}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20H%27%28x%29%20%3D%20%5Cfrac%7BF%27%28x%29%7D%7B3%5BF%28x%29%5D%5E%5Cbigg%7B%5Cfrac%7B2%7D%7B3%7D%7D%7D)
<u>Step 3: Evaluate</u>
- Substitute in <em>x</em> [Derivative]:
![\displaystyle H'(5) = \frac{F'(5)}{3[F(5)]^\bigg{\frac{2}{3}}}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20H%27%285%29%20%3D%20%5Cfrac%7BF%27%285%29%7D%7B3%5BF%285%29%5D%5E%5Cbigg%7B%5Cfrac%7B2%7D%7B3%7D%7D%7D)
- Substitute in function values:

- Exponents:

- Multiply:

- Simplify:

Topic: AP Calculus AB/BC (Calculus I/I + II)
Unit: Derivatives
Book: College Calculus 10e
The answer to the mathematics question presented above is 'True'. It is correct to say that in (r theta), the value of r can be negative. A negative radius can be used when it comes to graphing a "polar'' function. Thus, the answer to the question is 'true'.
Brady studied for 4.5 hours that week
How we determine the total study hours?
The total study hours for Brady is the sum of the hours used in studying on Monday, Tuesday, Wednesday and Thursday.
He studied for 1.5 hours on Monday
He studied for 0.75 hours on Tuesday
He studied again for 1.25 hours on Wednesday
Lastly, he studied for 1 hour on Thursday, the last day
Total number of study hours=1.5+0.75+1.25+1
Total number of study hours=4.50
Find out more about study hour on: brainly.com/question/876733
#SPJ1
Answer: no
Step-by-step explanation:
4÷5 equals 0.8
While 1 × 1/4 equals 0.25
Statement 3: tri egc = tri egb
statement 4: tri ebc is equilateral.
reason 5: equilateral triangles have equal angles